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professor190 [17]
3 years ago
6

Which steps would prove the circles similar?

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0

Answer:

You can translate smaller circle onto larger circle so centers line up and then dilate to prove similarity.

Step-by-step explanation:

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How do find the height of the parallelogram?
Yanka [14]
You need to multiply the base by the height.
5 0
3 years ago
What mathematicians helped to discover alternatives to euclidean geometry in the nineteenth century
Likurg_2 [28]

Answer:

Nikolai Lobachevsky and Bernhard Riemann

Step-by-step explanation:

Nikolai Lobachevsky (A russian mathematician born in 1792) and Bernhard Riemann (A german mathematician born in 1826) are the mathematicians that helped to discover alternatives to euclidean geometry in the nineteenth century.

7 0
3 years ago
After 3 hours of of driving, Paul had gone 183 miles. What was his average rate of speed? Explain your answer.
torisob [31]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

s(av) =  \frac{∆x}{∆t}  \\

s(av) = average \:  \: speed

∆x = covered \:  \: distance

∆t = time \:  \: of \:  \: the \:  \: covered \:  \: distance \\

_________________________________

s(av) =  \frac{183}{3}  \\

s(av) = 61 \:  \:  \frac{mile}{hour}

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

5 0
2 years ago
Item 8 Solve for x. Use the quadratic formula. 2x2−5x−9=0 Enter the solutions, in simplified radical form, in the boxes.
Lubov Fominskaja [6]

Answer:

5+√97/4

Also 5-√97/4

Step-by-step explanation:

The Quadratic formula is x=-b+-√b^2-4ac/2a

This means that we should plug the values for A B AND C into the formula

We can work out that

<u><em>A = 2</em></u>

<u><em>B=-5</em></u>

<u><em>C=-9</em></u>

Once we have put these into the formula we get

5+√97/4 (all over 4) aka 3.71

Also 5-√97/4 (all over 4) aka -1.21

7 0
3 years ago
Read 2 more answers
The vertices of a triangle are P(-1, 3), Q(2, -1), and R(5, 3).
Morgarella [4.7K]
Ok so to find which sides are congruent we need to know their lengths.

To find the length we need the distance formula between two point ->

√(X2-X1)∧2 +(Y2-Y1)∧2

Ok lets find the first side PQ

P(-1,3) Q(2,-1)
   X1 Y1  X2 Y2

√(2-(-1)∧2 + (-1-3)∧2 = 5

Now PR

P (-1,3) R (5,3)
    X1 Y1  X2 Y2

√(5-(-1))∧2 + (3-3)∧2) = 6

Now the last side QR

Q (2, -1) R (5,3)
   X1  Y1    X2 Y2

√(5-2)∧2 + (3-(-1))∧2 = 5

From the above work we see that PQ and QR are congruent becuase they are equal PQ=QR

Also the opposite angles of these sides are congruent. Hope this helps :).

8 0
3 years ago
Read 2 more answers
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