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2 years ago

Anyone wanna help a girl out?

Mathematics

2 answers:

VikaD [51]2 years ago

7 0

The two lines are neither
This is because in order for two lines to be considered parallel, they must have the same slope/ gradient. And none of our equations have the same slope/gradient
Whereas, in order for two lines to be considered perpendicular, their slopes/gradient must multiply together to give -1. And if we multiply the gradients of our equations, we do not get negative one

il63 [147K]2 years ago

7 0

Answer:

The two lines are neither

This is because in order for two lines to be considered parallel, they must have the same slope/ gradient. And none of our equations have the same slope/gradient

Whereas, in order for two lines to be considered perpendicular, their slopes/gradient must multiply together to give -1. And if we multiply the gradients of our equations, we do not get negative one

Step-by-step explanation:

You might be interested in

This is due in 10 minutes please help me

valkas [14]

Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Suppose x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.

$x\times \dfrac{7}{100}+2x\times \dfrac{8}{100}+3x\times \dfrac{9}{100}=150$

Multiplying both sides by 100, we get

$7x+16x+27x=15000$

$50x=15000$

Dividing both sides by 50, we get

$x=\dfrac{15000}{50}$

$x=300$

So, the amount invested at 7% is $300$ .

The amount invested at 8% is

$2(300)=600$

The amount invested at 9% is

$3(300)=900$

Hence, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

7 0

2 years ago

Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t

LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

$(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)$