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2 years ago

13x-7+7x-13=180 whats the answer?

Mathematics

2 answers:

Marianna [84]2 years ago

8 0

Answer:

x=10

Step-by-step explanation:

13x-7+7x-13=180

Combine like terms

20x-20 = 180

Add 20 to each side

20x -20+20 = 180+20

20x=200

Divide by 20

20x/20 = 200/20

x = 10

denis-greek [22]2 years ago

6 0

Answer:x=10

Step-by-step explanation:

1.add the number

2.add the same term to bothe sides of the equation

3.simplify

4.divide bothe side of the equation by the same term

5.simplify

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I want a way to solve this question

AURORKA [14]

Answer:

Step-by-step explanation:

Using the Cosine rule to find ∠ A

cosA = $\frac{b^2+c^2-a^2}{2bc}$

= $\frac{5.1^2+5.7^2-7.3^2}{2(5.1)(5.7)}$

= $\frac{26.01+32.49-53.29}{58.14}$

= $\frac{5.21}{58.14}$ , then

∠ A = $cos^{-1}$ ( $\frac{5.21}{58.14}$ ) ≈ 84.9° ( to 1 dec. place )

5 0

2 years ago

The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func

alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

$h(t)=-16t^2 + 96t$

Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

$To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq 0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq 0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)$

$Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq 0\\-112 \geq 0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq 0\\80 \geq 0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq 0\\-112 \geq 0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution$