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OLga [1]
3 years ago
6

Solve sin^2 theta*sec theta+cos theta= sec thetaSHOW WORK!!!

Mathematics
1 answer:
maks197457 [2]3 years ago
5 0
I think its sec theta
i havent done this in a while so... its prob wrong
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Table of inches and centimeters
TEA [102]

If you compare table values to answer choices, you can see right away that several don't work. The number of centimeters is greater than the number of inches, so adding to or multiplying the number of centimeters by some number more than 1 will not give you the smalller number that is inches.

While it may work for the first number (5 inches) to add 7.7 to get the first number of centimeters (12.7), you have to know that you can only add like to like. You can only add inches to inches (getting a result of inches), or centimeters to centimeters (getting a result of centimeters). From the point of view of the units involved, it is <em>nonsensical</em> to add a pure number to a number of inches and expect to get a number of centimeters.

So, we're down to the second choice:

- The number of inches is multiplied by 2.54 to find the number of centimeters.

_____

To find the pattern in the table, you can ...

  • observe that the inch values differ by 1
  • observe that the centimeter values differ by 2.54
  • realize that the constant differences mean the relation between inches and centimeters is linear, and that a change in an inch value of 1 inch is multiplied by 2.54 to find the corresponding change in centimeter value.

_____

I don't know what the first step in your problem solving process is supposed to be. In my problem solving process, the first step is always to <em>look at what you are given</em>. The next step is <em>look at what you are being asked for</em>.

8 0
3 years ago
Read 2 more answers
(a) Use the reduction formula to show that integral from 0 to pi/2 of sin(x)^ndx is (n-1)/n * integral from 0 to pi/2 of sin(x)^
Sedbober [7]
Hello,

a)
I= \int\limits^{ \frac{\pi}{2} }_0 {sin^n(x)} \, dx = \int\limits^{ \frac{\pi}{2} }_0 {sin(x)*sin^{n-1}(x)} \, dx \\&#10;&#10;= [-cos(x)*sin^{n-1}(x)]_0^ \frac{\pi}{2}+(n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos(x)*sin^{n-2}(x)*cos(x)} \, dx \\&#10;&#10;=0 + (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos^2(x)*sin^{n-2}(x)} \, dx \\&#10;&#10;= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {(1-sin^2(x))*sin^{n-2}(x)} \, dx \\&#10;= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx - (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^n(x) \, dx\\&#10;&#10;
I(1+n-1)= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\&#10;I= \dfrac{n-1}{n} *\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\&#10;

b)
\int\limits^{ \frac{\pi}{2} }_0 {sin^{3}(x)} \, dx \\&#10;= \frac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx \\&#10;= \dfrac{2}{3}\ [-cos(x)]_0^{\frac{\pi}{2}}=\dfrac{2}{3} \\&#10;&#10;&#10;&#10;&#10;

\int\limits^{ \frac{\pi}{2} }_0 {sin^{5}(x)} \, dx \\&#10;= \dfrac{4}{5}*\dfrac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx = \dfrac{8}{15}\\&#10;&#10;&#10;&#10;&#10;&#10;

c)

I_n=  \dfrac{n-1}{n} * I_{n-2} \\&#10;&#10;I_{2n+1}=  \dfrac{2n+1-1}{2n+1} * I_{2n+1-2} \\&#10;= \dfrac{2n}{2n+1} * I_{2n-1} \\&#10;= \dfrac{(2n)*(2n-2)}{(2n+1)(2n-1)} * I_{2n-3} \\&#10;= \dfrac{(2n)*(2n-2)*...*2}{(2n+1)(2n-1)*...*3} * I_{1} \\\\&#10;&#10;I_1=1\\&#10;&#10;




3 0
4 years ago
Mr Oneill bought cheese, turkey slices and wheat rolls for $55. The ratio of the amount of money spent on cheese to the amount o
astra-53 [7]

Answer:

Mr. O'neill buy 33 turkey slices.

Step-by-step explanation:

Firstly let us denote <em>amount of money spent on Cheese by the symbol C.</em>

<em>                                  amount of money spent on Turkey by the symbol T.</em>

<em>                                   amount of money spent on Wheat by the symbol W.</em>

Now we are the ratio of amount of money spent on cheese to the amount of money spent on turkey slices as 2:3 ;

       We can represent this as  \frac{C}{T} = \frac{2}{3}

The ratio of the amount of money spent on cheese to the amount of money spent on wheat rolls is 6:5 ;

        We can represent this as  \frac{C}{W} = \frac{6}{5}

Now we will make C also 6 in the first ratio to represent similarity in ratios i.e.     \frac{C}{T} = \frac{2 * 3}{3 * 3} = \frac{6}{9}

So, the ratio of amount of money spent on cheese to the amount of money spent on turkey slices to the amount of money spent on wheat rolls is represented by 6 : 9 : 5.

To find the amount of money spent on turkey slices = \frac{9}{6+9+5} * $55 = $24.75

Since cost of each turkey slice cost = $ 0.75

Therefore, Cost of each turkey slice * Number of turkey slices = Total amount of money spent on turkey slices

    $0.75 * Number of turkey slices = $24.75

Therefore, Number of turkey slices that Mr. O'neill buy = $24.75/$0.75

                                                                                            = 33 slices.

4 0
3 years ago
Which of the following is not a way to represent the solution of the inequality 2(x− 1) ≤ 10?
sertanlavr [38]

Answer: D. A number line with a closed circle on 6 and shading to the right

Step-by-step explanation:

Here, the given inequality,

2(x− 1) ≤ 10

2x - 2 ≤ 10

2x ≤ 10 + 2

2x ≤ 12

x ≤ 6 or 6 ≥ x

The value of x is all numbers less than 6 including 6.

⇒ A number line with a closed circle on 6 and shading to the left.

Thus, by the above explanation,

Only option D 'A number line with a closed circle on 6 and shading to the right' is not a way to represent the solution of the inequality.

4 0
4 years ago
Read 2 more answers
Please answer correctly! I will mark you Brainliest!
weeeeeb [17]

Answer:

4.1 inches

<u>I would appreciate Brainliest, but no worries.</u>

4 0
3 years ago
Read 2 more answers
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