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3 years ago

Find the limit as x approaches 25: x-25 √x-5

Mathematics

1 answer:

yawa3891 [41]3 years ago

8 0

x - 25 = (√x)^2 - 5^2 = (√x - 5)(√x + 5)

Then

(x - 25)/(√x - 5) = √x + 5

and as x approaches 25, we get a limit of √25 + 5 = 5 + 5 = 10.

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Hi there!

Let x equal to the smaller number.

Let y be equal to the greater number.

1) Translate the information into equations

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Plug the equation $y=2x+7$ into the above equation

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I hope this helps!

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