For a right triangle with legs legnth a and b and hyptonuse c
a^2+b^2=c^2
9 feet from base, that's one leg
wire is hypotnuse, it's 1 more than height on tree
c=b+1
so
9^2+b^2=(b+1)^2
81+b^2=b^2+2b+1
minus b^2+1 from both sides
80=2b
divide both sides by 2
40=b
c=b+1
c=40+1
c=41
legnth of wire is 41ft
Answer:
D
Step-by-step explanation:
Answer:
34 cm
Step-by-step explanation:
Keep in mind that the perimeter of a rectangle is the sum of the measures of its sides. This means that the sum of the longer sides and the shorter sides is the perimeter of the rectangle.
Let "L" represent the longer side (length) of the rectangle and "S" represent the shorter side (width) of the rectangle.
⇒ Perimeter of rectangle = L + S + L + S
⇒ Perimeter of rectangle = 2(L) + 2(S)
⇒ Perimeter of rectangle = 2(L + S)
Now, let's substitute the length and the width in the perimeter and simplify.
⇒ Perimeter of rectangle = 2(10 + 7) [L = 10; S = 7]
⇒ Perimeter of rectangle = 2(17)
⇒ Perimeter of rectangle = 34 cm
