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2 years ago

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2 answers:

Fiesta28 [93]2 years ago

5 0

Answer:

1.15

Step-by-step explanation:

diamong [38]2 years ago

4 0

What’s the question? Can I buy some cookies?

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Students in an art class cut colored paper into equal-sized squares. The paper measures 6 cm by 12 cm and they do not want to wa

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The greatest possible side length is 24 square piece

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3 years ago

What is the value of the hypotenuse below

Dmitry [639]

Answer:

H= 10

Step-by-step explanation:

Hypotenuse formula if you have the other 2 sides.

$\sqrt{a^{2} }+b^{2}$

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3 years ago

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What is 8 divided by 645 in 5th grade

Tatiana [17]

That equals <u>.0124031008</u>

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3 years ago

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6^2r=800 round it to the nearest hundreth

kogti [31]

Question: solve for r: 6 ^ (2r) = 800

Answer: 1.87

Step-by-step explanation:

6 ^ (2r) = 800

log(6 ^ (2r)) = log(800)

2r log(6) = log(800)

r = log(800) / (2 log(6))

r = 1.86537641979

round

r = 1.87

log can be any logarithm function.

6^(2×1.86) = 784.734328546

6^(2×1.87) = 813.365367336

7 0

3 years ago

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

2 years ago