Answer:
(4, 1)
Step-by-step explanation:
x^2 + y^2 - 2y - 8x - 19 = 0
We rearrange the terms and complete the square twice.
x^2 - 8x + y^2 - 2y = 19
x^2 - 8x + 16 + y^2 - 2y + 1 = 19 + 16 + 1
(x - 4)^2 + (y - 1)^2 = 6^2
The center is (4, 1)
Answer:
<h2>
<u>x=12480</u></h2>
Step-by-step explanation:
Step 1: Add 24 to both sides.
1
/312
x−24+24=16+24
1
/312
x=40
Step 2: Multiply both sides by 312.
312*(
1
/312
x)=(312)*(40)
x=12480
9514 1404 393
Answer:
CPCTC
Step-by-step explanation:
The applicable reason for statement 4 is "Corresponding Parts of Congruent Triangles are Congruent (CPCTC)".
The reason shown in your problem statement is applicable only within one triangle. The segments of interest are in two different triangles.
Answer:
Given, 3x−2<2x+1
⇒3x−2x<1+2
⇒x<3orx∈(−∞,3)
The lines y=3x−2 and y=2x+1 both will intersect at x=3
Clearly, the dark line shows the solution of 3x−2<2x+1.
Step-by-step explanation:
