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3 years ago

Which expressions are equivalent to 12-14/3m+2/3m?

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

The answer
Is A/B/C those are all that apply

You might be interested in

Given that f(x) = x² + 3x 28 and g(x) = x + 7, find f(x) + g(x) and

ozzi

Answer:

f(x) + g(x) = x^2 + 4x + 35

Step-by-step explanation:

Add like terms from f(x) and g(x):

f(x) + g(x) = x^2 + 3x + 28 + x + 7, or

f(x) + g(x) = x^2 + 4x + 35

7 0

2 years ago

What does x+x+x+x+x-1+1+1+1= ? (Giving this for 30 points)

77julia77 [94]

First, let's add all the x's.

x + x + x + x + x = 5x

5x - 1 + 1 + 1 + 1

Now, let's add together all the 1's that are being added (not the 1 that is being subtracted from 5x).

1 + 1 + 1 = 3

5x - 1 + 3

3 - 1 = 2

5x + 2

There's no way you can actually solve this unless you know the value of x; without x's value, this is as simplified as the expression is going to get.

Hope this helps!

7 0

2 years ago

Read 2 more answers

What is the radius if the Diameter 10.5? r = 8.5 r = 5.25 r = 12.5 r = 21

nataly862011 [7]

If the diameter is 10.5 then the radius is 5.25.
This is because the radius of a diameter is half the diameter.

So

10.5/2
= 5.25

Therefore the radius is 5.25

6 0

2 years ago

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

2 years ago

I will be back to help you guys

Luda [366]

Answer:

thx u xox ur so sweet

Step-by-step explanation:

3 0

2 years ago