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tino4ka555 [31]

2 years ago

12

A landscaper plants 18 bushes in a 36-foot section of land along the side of a house. How many bushes does the landscaper plant

in a 10-foot section of land?
5

8

12

20

1 answer:

fenix001 [56]2 years ago

5 0

Answer:

know I'm going off my

math skills but I think its 12 or 5 .trust me its not 20 I tried

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Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

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5 0

2 years ago

Someone please help me!! I don’t know the answer!!

coldgirl [10]

Answer:

Step-by-step explanation:

Remark

The measurement of the arc is 3Pi

that represents 108 / 360 of the circle.

Equation

108/350 2 * pi * R = 3* pi

Solution

Pi is on both sides of the equation. They both cancel.

108/360 = 0.3

0.3 * 2 * R = 3

0.6 * R = 3

R = 3/0.6

R = 5

8 0

2 years ago

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Wich function is described by the value in the table

kolbaska11 [484]

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3 0

2 years ago

A laundry mat can clean five shirts in 20 minutes. What is the rate of shirts per hour?

Anna11 [10]

Answer:

15 shirts in one hour

Step-by-step explanation:

there are 60 minutes in an hour, 20 times 3 is 60, 5 times 3 is 15

5 0

3 years ago

Which expression is equivalent to the following complex fraction? <br><br>(pls help me out)

const2013 [10]

Answer:

B. $\frac{-4x + 7}{2(x - 2)}$

Step-by-step explanation:

Simplify the given expression to determine its equivalent expression in the given options.

$\frac{\frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1}}$

$\frac{\frac{3}{x - 1} - \frac{4}{1}}{\frac{2}{1} - \frac{2}{x - 1}}$

$\frac{\frac{3 - 4(x - 1)}{x - 1}}{\frac{2(x - 1) - 2}{x - 1}}$

$\frac{\frac{3 - 4x + 4}{x - 1}}{\frac{2x - 2 - 2}{x - 1}}$

$\frac{\frac{-4x + 7}{x - 1}}{\frac{2x - 4}{x - 1}}$

$\frac{-4x + 7}{x - 1} * \frac{x - 1}{2x - 4}$

(x - 1) cancels (x - 1)

$\frac{-4x + 7}{1} * \frac{1}{2x - 4}$

$\frac{(-4x + 7)1}{1(2x - 4)}$

$\frac{-4x + 7}{2x - 4}$

$\frac{-4x + 7}{2(x - 2)}$

3 0

3 years ago