Answer:
Y' = -xsin(2x) + 2cos(2x)
Step-by-step explanation:
For this problem, we will need to use the product rule since you have two terms that contain the variable x.
The product rule is simply as follows:
The derivative of the function is the product of the first term times the derivative of the second term plus the derivative of the first term times the second term.
Note the derivative of 2x with respect to x, is 2.
Note the derivative of cos(2x) with respect to x is (-1/2) sin(2x).
With this in mind, let's find the derivative of our function with respect to x.
Y = 2xcos2x
Y = 2x * cos(2x)
Y' = 2x * (-1/2)sin(2x) + 2 * cos(2x)
Y' = (2x * -1 / 2) sin(2x) + 2 * cos(2x)
Y' = (-x)sin(2x) + 2cos(2x)
So the derivative of our function is Y' = -xsin(2x) + 2cos(2x) according to the application of the product rule.
Cheers.
Answer:
Step-by-step explanation:
Hope this helps!
<span>The equation given as p varies directly with d and inversely with the square root of u is written as:
</span>
p = k1d
k1 is the proportionality constant.
and p = k2
here k2 is the proportionality constant.
Thus,
combining both equations we get, p = C
where K = K1*K2, K is the proportionality constant.
Y = x - 7 ---------- (1)
5x + 2y = 7 ------ (2)
Sub (1) into (2):
5x + 2(x -7) = 7
5x + 2x - 14 = 7
7x - 14 = 7
7x = 7 + 14
7x = 21
x = 3 ----- -sub into (1)
y = x - 7
y = 3 - 7
y = -4
Ans: x = 3, y = -4
I think If I'm reading this correctly the 7/8 piece is longer.
7/8 = 0.875
2/8 = .25
So 7/8 is longer
I hope this helps :)
