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Brums [2.3K]
2 years ago
12

William is adding 14+ (-3). He wants to write 14 as the sum of two numbers so that one of the numbers, when added to -3, will eq

ual 0. How should
William write 14 to complete this problem?
Write integers in the blanks to show how William will solve this problem.
14+(-3) =_+_+(-3)
14+(-3)=_+0
Mathematics
1 answer:
seraphim [82]2 years ago
4 0

Answer: Below

Step-by-step explanation:

14+(-3) =11+3+(-3)

14+(-3)=11+0

I hope this helped!

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The property taxes on a business were $1035. What was the tax rate of the business office was valued at $115,000?
olya-2409 [2.1K]

Answer:

The rate of tax is 0.9% of the actual business amount.

Step-by-step explanation:

Given that:

Tax amount = $1035

Business value = $115,000

So, for finding the rate, we will have to divide the tax amount by business value and multiply it by 100 as follows:

Rate = 1035/115,000 * 100

By simplifying we get:

Rate = 0.009 *100

Rate = 0.9 %

This means that the tax rate is 0.9% of the original amount.

i hope it will help you!

7 0
3 years ago
What’s the sum of 20x^2-10x-30
Vladimir [108]
10(x+1)(2x−3) I think
8 0
3 years ago
Read 2 more answers
Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite
zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt  be a gram/L

Let the amount salt in the tank at any time t be Q(t).

\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}

Incoming rate = (a g/L)×(1 L/min)

                       =a g/min

The concentration of salt in the tank at any time t is = \frac{Q(t)}{10}  g/L

Outgoing rate = (\frac{Q(t)}{10} g/L)(1 L/ min) \frac{Q(t)}{10} g/min

\frac{dQ}{dt} = a- \frac{Q(t)}{10}

\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt

Integrating both sides

\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt

\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c        [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c

\Rightarrow -log|10a-15|-2=c

Therefore ,

-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2 .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0  in equation (1) we get

- log|10a|= -log|10a-15| -2

\Rightarrow- log|10a|+log|10a-15|= -2

\Rightarrow log|\frac{10a-15}{10a}|= -2

\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}

\Rightarrow 1-\frac{15}{10a} =e^{-2}

\Rightarrow \frac{15}{10a} =1-e^{-2}

\Rightarrow \frac{3}{2a} =1-e^{-2}

\Rightarrow2a= \frac{3}{1-e^{-2}}

\Rightarrow a = 1.73

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0
3 years ago
A sprinkler head turns through 40 one–degree angles every minute. What is the measure of the angle the sprinkler head turns afte
bixtya [17]

Answer:

20

Step-by-step explanation:

3 0
2 years ago
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What is the coefficient of the xy term in the expression below? <br> 2x + 3y - 4xy - 10
alukav5142 [94]

For this case we have the following expression:

2x + 3y-4xy-10

By definition, a coefficient is the term that accompanies one or more variables.

For example:

3x + 5

The coefficient of the linear term is 3.

So, in the given expression we have to:

-4 is the term that accompanies the variables xy.

Answer:

-4

3 0
3 years ago
Read 2 more answers
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