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nikklg [1K]
3 years ago
10

Show step to solve 3(t+4)-2(2t+3)=-4

Mathematics
2 answers:
Oksanka [162]3 years ago
8 0

Answer:

t=10

Step-by-step explanation:

3*(t+4)-2*(2*t+3)-(-4)=0

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((3 • (t + 4)) -  2 • (2t + 3)) -  -4  = 0

Step  2  :

Equation at the end of step  2  :

 (3 • (t + 4) -  2 • (2t + 3)) -  -4  = 0

Step  3  :

Equation at the end of step  3  :

 10 - t  = 0

Step  4  :

Solving a Single Variable Equation :

4.1      Solve  :    -t+10 = 0

Subtract  10  from both sides of the equation :

                     -t = -10

Multiply both sides of the equation by (-1) :  t = 10

baherus [9]3 years ago
6 0

Answer: t = 10

Step-by-step explanation:

Reorder the terms:

12 + 3t + -2(3 + 2t) = -4

12 + 3t + (3 * -2 + 2t * -2) = -4

12 + 3t + (-6 + -4t) = -4

Reorder the terms:

12 + -6 + 3t + -4t = -4

Combine like terms: 12 + -6 = 6

6 + 3t + -4t = -4

Combine like terms: 3t + -4t = -1t

6 + -1t = -4

Solving

6 + -1t = -4

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + -1t = -4 + -6

Combine like terms: 6 + -6 = 0

0 + -1t = -4 + -6

-1t = -4 + -6

Combine like terms: -4 + -6 = -10

-1t = -10

Divide each side by '-1'.

t = 10

Simplifying

t = 10

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Answer:

22.5

Step-by-step explanation:

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5 0
3 years ago
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Dafna1 [17]

Answer:

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Step-by-step explanation:

For Q1 and Q2

\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U

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For Q3 and Q4

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4 0
4 years ago
Devin has a snake. The snake eats one mouse every week which Devin purchases from the local pet store. If m represents the cost
n200080 [17]
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3 years ago
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5 0
4 years ago
A 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia). At a summer cam
bagirrra123 [75]

Answer:

Probability that at least one of them suffers from arachnophobia is 0.5160.

Step-by-step explanation:

We are given that a 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia).

Also, At a summer camp there are 10 teenagers sleeping in each tent.

Firstly, the binomial probability is given by;

P(X=r) =\binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,....

where, n = number of trials(teenagers) taken = 10

           r = number of successes = at least one

          p = probability of success and success in our question is % of

                the teenagers suffering from arachnophobia, i.e. 7%.

Let X = Number of teenagers suffering from arachnophobia

So, X ~ Binom(n= 10,p=0.07)

So, probability that at least one of them suffers from arachnophobia

= P(X >= 1) = 1 - probability that none of them suffers from arachnophobia

= 1 - P(X = 0) = 1 - \binom{10}{0}0.07^{0}(1-0.07)^{10-0}

                       = 1 - (1 * 1 * 0.93^{10} ) = 1 - 0.484 = 0.5160 .

Therefore, Probability that at least one of them suffers from arachnophobia is 0.5160 .

3 0
3 years ago
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