A rectangular field is fully enclosed with 218 meters of fencing. The length of the field is
1 answer:
The length and width of a rectangular field fully enclosed with 218 metes fencing are 63 meters and 46 meters respectively.
The perimeter of a rectangle is the sum of the whole four sides. Therefore, the perimeter of a rectangle is defined as follows:
where
l = length
w = width
perimeter = 218 meters
The length of the field is 17 meters longer than the width, w. Therefore, the length is defined as follows:
The length and the width can be calculated as follows:
218 = 2(l + w)
218 = 2(17 + w + w)
218 = 34 + 4w
218 - 34 = 4w
184 = 4w
divide both sides by 4
w = 184 / 4
w = 46 meters
length = 17 + 46
length = 63 meters
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Cube both sides
remember PEMDAS
parentheses
Exponents
Multiplication
Division
Addition
Subtraction
Answer:
-4 -23i
Step-by-step explanation:
(4-16i) - (8+7i)
Distribute the minus sign
4-16i -8-7i
Combine like terms
4-8 -16i -7i
-4 -23i
P=2(l+w)
Substitute width plus 3 for length
Remember order of operations: multiply before adding
86=2((w+3) + w)
86=2w+6+2w
86=4w+6
80=4w
20=w
23=w+3=l
Check the answer
86=2((w+3) + w)
86=2((20+3)+20
86=2(23+20)
86=46+40
86=86
Answer:18
Step-by-step explanation:
Every third term is a sum of previous two.
the sequence 1, 3, 4, 7, 11, 18
