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Anon25 [30]
3 years ago
7

Emanuel was charged \$32$32dollar sign, 32 for a 14\dfrac29 \text{ km}14 9 2 ​ km14, start fraction, 2, divided by, 9, end fract

ion, space, k, m taxi ride. What was the cost per kilometer? \$Emanuel was charged \$32$32dollar sign, 32 for a 14\dfrac29 \text{ km}14
9

2

​ km14, start fraction, 2, divided by, 9, end fraction, space, k, m taxi ride.

What was the cost per kilometer?
Mathematics
2 answers:
zaharov [31]3 years ago
8 0

Answer:

$2.25/km

Step-by-step explanation:

The cost charged for a total taxi ride of 14\frac{2}{9}\ km was $32. To get the cost per km, we divide the cost charged for the total taxi ride by the total distance that was traveled by the taxi. The cost per km is given by:

Cost per km = \frac{Cost \ of\ money\ charged}{Total\ distance}=\frac{\$ 32}{14\frac{2}{9} \ km}=\frac{32}{\frac{128}{9} }=   \$2.25/km

Therefore the cost per kilometer is $2.25 per kilometer. Each kilometer traveled by the taxi cost $2.25.

VladimirAG [237]3 years ago
3 0
The answer is $2.25 km
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One formula for the reproduction of bacteria is

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9514 1404 393

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  ∠KXN and ∠QXT

Step-by-step explanation:

The measure of each angle is the difference of the scale values that the rays intercept. (The same scale needs to be used for each ray.) Of course, complementary angles have a sum of 90°.

Here, we'll refer to angle aXb as "ab".

  NP = 95 -35 = 60

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  KN = 165 -95 = 70

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Step-by-step explanation:

Given the geometric sequence

8 + 6 + 4.5...

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r=\frac{3}{4}

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=8

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=8\left(\frac{3}{4}\right)^{n-1}

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=25,\:\spacea_1=8,\:\spacer=\frac{3}{4}

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\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

=\frac{\left(1-\left(\frac{3}{4}\right)^{25}\right)\cdot \:8}{1-\frac{3}{4}}

=\frac{8\left(-\left(\frac{3}{4}\right)^{25}+1\right)}{\frac{1}{4}}

\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}

=\frac{8\left(-\frac{3^{25}}{4^{25}}+1\right)}{\frac{1}{4}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}

=\frac{\left(1-\frac{3^{25}}{4^{25}}\right)\cdot \:8\cdot \:4}{1}

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=\frac{32\left(-\frac{3^{25}}{4^{25}}+1\right)}{1}

=\frac{32\cdot \frac{4^{25}-3^{25}}{4^{25}}}{1}               ∵ \mathrm{Join}\:1-\frac{3^{25}}{4^{25}}:\quad \frac{4^{25}-3^{25}}{4^{25}}

=32\cdot \frac{4^{25}-3^{25}}{4^{25}}

=\frac{\left(4^{25}-3^{25}\right)\cdot \:32}{4^{25}}

=\frac{2^5\left(4^{25}-3^{25}\right)}{2^{50}}        ∵ \mathrm{Factor}\:32:\ 2^5,  \mathrm{Factor}\:4^{25}:\ 2^{50}

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\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a\pm \:b}{c}=\frac{a}{c}\pm \frac{b}{c}

=\frac{4^{25}}{2^{45}}-\frac{3^{25}}{2^{45}}      

=32-\frac{3^{25}}{2^{45}}            ∵  \frac{4^{25}}{2^{45}}=32

=32-0.024        ∵  \frac{3^{25}}{2^{45}}=0.024

=31.98            

Therefore, the sum of the first 25 terms in this geometric series: 31.98

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