Answer:
In disguise right arrow In Standard Form a, b and c
x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1
2(w2 − 2w) = 5 Expand (undo the brackets),
and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5
z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3
Step-by-step explanation:
sorry it took so long
Answer:
A, B, F
Step-by-step explanation:
2/3 - x + 1/6 = 6x
Collect like terms
2/3 + 1/6 = 6x + x
(4+1) / 6 = 7x
5/6 = 7x
x = 5/6 ÷ 7
= 5/6 × 1/7
x = 5/42
a) 4 - 6x + 1 = 36x
4 + 1 = 36x + 6x
5 = 42x
x = 5/42
Equivalent to the last step of the simplification above
b) 5/6 - x = 6x
5/6 = 6x + x
5/6 = 7x
This is equivalent to the third step of the simplification
c) 4 - x + 1 = 6x
4 + 1 = 6x + x
5 = 7x
x = 5/7
Not equivalent to any of the steps in the simplification above
d) 5/6 + x = 6x
5/6 = 6x - x
5/6 = 5x
x = 5/6 ÷ 5
= 5/6 × 1/5
x = 5/30
Not equivalent to any of the steps in the simplification above
e) 5 = 30x
x = 5/30
Not equivalent to any of the steps in the simplification above
f) 5 = 42x
x = 5/42
Equivalent to the last step of the simplification above
Answer:
a = 112
Step-by-step explanation:
Given that,
s = 7
b = 13
c = (-24)
Let's solve for a now.
Hope this helps you.
Let me know if you have any other questions :-)
Answer:
Step-by-step explanation:
a.
2y - 3x = 5
2(-2) - 3x = 5
-4 - 3x = 5
-3x = 9
x = -3
(-3,-2) is another solution
b.
(-1,1)
2y - 3x = 5
2(1) - 3(-1) = 5
2 + 3 = 5
5 = 5
true, the point is a solution to the equation because the equation is true after substituting x and y with the point (-1,1)
(4,1)
2y - 3x = 5
2(1) - 3(4) = 5
2 - 12 = 5
-10 = 5
not true, the point is not a solution to the equation because the equation is not true after substituting x and y with the point (4,1)
c. You can use the points from the given (-1,1) and (-3,-2) to form a line. You then shade whichever half solves the solution using points on the graph.
