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kobusy [5.1K]
3 years ago
13

Help plz this is due tomorrow

Mathematics
2 answers:
ella [17]3 years ago
6 0
Just covert the fractions into the greatest common factor and then add 5+6 with the fractions which 1/5 would be 4/20 because 1/5 times 4/4 = 4/20 and then covert 1/4 into 5/20 and then add 4/20+5/20 together and then subtract by 13 which would be G. 
scZoUnD [109]3 years ago
3 0
13-11 9/20 = 1 11/20 sooo G
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Using the slope formula, find the slope of the line through the given points. (4.4) and (5.2) What is the slope of the line? Sel
harina [27]

Answer:

A.

m = -1

Step-by-step explanation:

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Simply plug in your 2 coordinates into the formula to find slope <em>m</em>:

m = (6 - 4)/(2 - 4)

m = 2/-2

m = -1

3 0
3 years ago
A company has 2 machines that manufacture widgets. An older machine manufactures 25% defective widgets, while the new machine ma
Bingel [31]

Answer:

73.90%

Step-by-step explanation:

Let Event D=Defective,  D' = Non Defective

Let Event N=New Machine, N' = Old Machine

From the given information:

P(D|N')=0.25\\P(D|N)=0.09\\P(N)=0.7\\P(N')=0.3

We are required to calculate the probability that a widget was manufactured by the new machine given that it is non defective.  

i.e. P(N|D')

P(D'|N')=1-P(D|N')=1-0.25=0.75\\P(D'|N)=1-P(D|N)=1-0.09=0.91

Using Baye's Law of conditional Probability

P(N|D')=\dfrac{P(D'|N)P(N)}{P(D'|N)P(N)+P(D'|N')P(N')} \\=\dfrac{0.91*0.7}{0.91*0.7+0.75*0.3}\\ =0.73897\\\approx 0.7390

Therefore given that a selected widget is non-defective, the probability that it was manufactured by the new machine is 73.9%.

5 0
3 years ago
Suppose that IQ scores have a bell-shaped distribution with a mean of 99 and a standard deviation of 14. Using the empirical rul
algol [13]

Answer:

About 99.7% of the IQ scores would be between 57 and 141.

Step-by-step explanation:  

The Empirical Rule about a bell-shaped curve states that :

  • 68% of the data lies within one standard deviation of the mean (both left-side and right-side)
  • 95% of the data lies within two standard deviations of the mean (both left-side and right-side)
  • 99.7% of the data lies within three standard deviations of the mean (both left-side and right-side)

Now, we need to find what percentage of IQ scores lies between 57 and 141 : Mean = 99 and standard deviation = 14

141 – 99 = 42

              = 3 × 14

Thus, 141 is 3 standard deviations to the right of the mean.

99 – 57 = 42

              = 3 × 14

Thus, 57 is 3 standard deviations to the left of the mean.

Since 57 to 141 is within 3 standard deviations of the mean, and according to empirical formula stated above : about 99.7% of the IQ scores would be between 57 and 141.

8 0
3 years ago
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
In certain city, it was recorded that 14 2/3 inches of rain fell over a 24-hour period. How much rain fell per hour on average
sergeinik [125]
6/10 rounded to the nearest tenth inches a hour of rain fell
3 0
3 years ago
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