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3 years ago

1. 108 identical books have a mass of 30 kg. Find

Mathematics

1 answer:

AURORKA [14]3 years ago

8 0

Answer:

i) around 41.7 kg

ii) 72 books

Step-by-step explanation:

i) if 108 books are 30 kg then how much is the mass for 150? You cross multiply so 150 multiply by 30 and 108 multiply by x (the unknown mass). you will get 4500=108x and then 4500/108 is the unknown mass.

ii) use the same way as above.

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3 years ago

What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.

Paul [167]

Answer:

1.60 $ft^{2}$

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = $\pi$ $r^{2}$

So that,

for the inner part of the pipe,

r = $\frac{diameter}{2}$

= $\frac{5}{2}$

= 2.5 feet

Area of the inner part of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.5)^{2}$

= 19.625

Are of the inner part of the pipe is 19.63 $ft^{2}$ .

Total diameter of the pipe = 5 + 0.2

= 5.2 feet

r = $\frac{5.2}{2}$

= 2.6 feet

Area of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.6)^{2}$

= 21.2264

Area of the pipe is 21.23 $ft^{2}$ .

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= 21.2264 - 19.625

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6 0

2 years ago

The drama club is selling tickets to its play. An adult ticket costs $15 and a student ticket costs $11. The auditorium will sea

spin [16.1K]

Answer:

83 adult tickets and 217 student tickets.

Step-by-step explanation:

Let number of adult tickets sold = $x$

Given that total number of tickets = 300

So, number of student tickets = 300 - $x$

Cost of adult ticket = $15

Cost of student ticket = $11

Total collection from adult tickets = $ $15x$

Total collection from student tickets = $(300-x)\times 11 = 3300-11x$

Given that overall collection = $3630

$15x+(3300-11x) = 3630\\\Rightarrow 15x-11x=3630-3300\\\Rightarrow 4x = 330\\\Rightarrow x = 82.5$

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.

Now , collection = $3632

4 0

3 years ago