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3 years ago

The quotient of a number and 15 is no greater than 450. What are the possible values. For the number?

1 answer:

5 0

A number can be represented by n. So n/15≤450 then multiply both sides by 15 to get n by itself n≤6,750 Hope this helped!!! :)

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The Thompson family borrowed $120,000

kolezko [41]

Answer:

27,600

Step-by-step explanation:

6 0

3 years ago

Order the numbers from greatest to least? 2/9, 21%, 5/20, 8%

Elena-2011 [213]

Answer:

5/20, 2/9, 21%, 8%

Step-by-step explanation:

2/9 = 0.22

21% = 0.21

5/20 = 0.25

8% = 0.08

0.25>0.22>0.21>0.08

mark brainliest please!

8 0

1 year ago

What is the product? (9t − 4)(−9t − 4) −81t2 − 16 −81t2 16 −81t2 − 72t 16 −81t2 72t 16

Alexxandr [17]

We have to find the product : ( 9 t - 4 ) ( - 9 t - 4 ) = - ( 9 t - 4 ) ( 9 t + 4 ) After that we can use the difference of squares. The formula is: ( a + b ) ( a - b ) = a^2 - b^2. In this case: - ( 9 t - 4 ) ( 9 t + 4 ) = - ( 81 t^2 - 16 ) = - 81 t^2 + 16 . Answer: B ) - 81 t^2 + 16.

5 0

3 years ago

Solve this simultaneous equation x+2y=11 x-2y=1

lana [24]

Answer:

Equation 1,

$x + 2y = 11$

Equation 2,

$x - 2y = 11$

Take equation number 2.

$x - 2y = 11 \\ x = 11 + 2y$

Substitute 'x' in Equation number 1.

$x + 2y = 11 \\ 11 + 2y + 2y = 11 \\ 11 + 4y = 11 \\ 4y = 11 - 11 \\ 4y = 0 \\ y = \frac{0}{4} \\ y = 0$

y = 0.

So x,

$x = 11 - 2y \\ x = 11 - 2(0) \\ x = 11 - 0 \\ x = 11$

x = 11.

7 0

3 years ago

Read 2 more answers

Give the equation of the line perpendicular to y +7= -2(x - 6) through the point (6,-3)

lilavasa [31]

Note: this answer assumes the equation of the line can be put in slope-intercept form.

Answer:

$y + 3 = \frac{1}{2}(x-6)$

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or $y-y_1 = m (x-x_1)$ format. Remember that the number in place of the $m$ is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction ( $-\frac{2}{1}$ ), and flip its numerators and denominators. Therefore, the perpendicular slope would be $\frac{1}{2}$ .

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, $y-y_1 = m (x-x_1)$ . In order to write an equation, the $x_1$ , $y_1$ , and $m$ have to be substitute for with real values.

The $m$ represents the slope. We already calculated that in the last step, so put $\frac{1}{2}$ in place of the $m$ . The $x_1$ and $y_1$ represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for $x_1$ and -3 for $y_1$ :

$y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)$

Therefore, (again, assuming that the line can be put in point-slope form) the answer is $y + 3 = \frac{1}{2}(x-6)$ .

5 0

3 years ago