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SIZIF [17.4K]
4 years ago
13

Rewrite y-2=3(x-1) in standard form

Mathematics
1 answer:
erica [24]4 years ago
6 0
Y - 2 = 3(x - 1)
y - 2 = 3x - 3
y = 3x - 3 + 2
y = 3x - 1
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Is this a parallelogram, rectangle, rhombus, and/or square and how
NeTakaya
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A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then
Ivan

Complete question is;

A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 18 minutes.

a. What equation can you use to find the distance of the flowerbed from the hive?

b. How far is the flowerbed from the hive?

Answer:

A) (d/9) + 900 + (d/6) = 1080

B) d = 648 ft

Step-by-step explanation:

A) We are told that A bee flies at 9 feet per second directly to a flower bed from its hive.

Time taken is given as;

t = distance/speed

If distance is d from the hive to the flower bird.

Then, t1 = d/9

The bee stays at the flowerbed for 15 minutes. Thus, time spent at the flowerbird in seconds is; t2 = 15 × 60 = 900 seconds.

We are told that the bee flew directly back to the hive at 6 feet per second.

Thus,time is;

t3 = d/6

Since total time spent away from hive is 18 minutes, then converting to seconds, we have; t = 18 × 60 = 1080 s

Thus;

(d/9) + 900 + (d/6) = 1080

B) Since we have derived;

(d/9) + 900 + (d/6) = 1080

Then we can find d.

Multiply through by 18 to get;

2d + (900 × 18) + 3d = 1080 × 18

2d + 16200 + 3d = 19440

5d = 19440 - 16200

5d = 3240

d = 3240/5

d = 648 ft

4 0
3 years ago
What is the area of this
AveGali [126]

Answer:

12m

Step-by-step explanation:

3 0
3 years ago
A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and
goblinko [34]

Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

where;

F= force applied on the spring

x = the extension on the spring

k= the spring constant which varies in spring.

The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

Here the spring extension is 15 m

<u>In spring B</u>

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

<u>Compare</u>

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

=15m-12m=3m

5 0
3 years ago
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