Ask question

Ask question

All categories

3 years ago

7

A circle has a radius of 13 cm what is the diameter of the circle? What is the circumference of the circle? What is the area of

the circle? Step-by-step answer please

1 answer:

SVEN [57.7K]3 years ago

4 0

Answer:

Diameter: 26cm

Circumference: 26π / 81.68cm

Area: 169π / 531cm²

Step-by-step explanation:

Diameter is radius x 2, so 13 x 2 = 26

Circumference is diameter x π, so 26 x π = 26π / 81.68cm

Area is π x r², so π x 13² = 169π / 531cm²

You might be interested in

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$

a) Determine the 26th percentile for the number of chocolate chips in a bag. 

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

$Z = \frac{X - \mu}{\sigma}$

$-0.643 = \frac{X - 1262}{118}$

$X - 1262 = -0.643*118$

$X = 1186$

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{X - 1262}{118}$

$X - 1262 = -1.96*118$

$X = 1031$

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

$Z = \frac{X - \mu}{\sigma}$

$1.96 = \frac{X - 1262}{118}$

$X - 1262 = 1.96*118$

$X = 1493$

Between 1031 and 1493.

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 1262}{118}$

$X - 1262 = -0.675*118$

$X = 1182$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 1262}{118}$

$X - 1262 = 0.675*118$

$X = 1342$

IQR:

1342 - 1182 = 160

7 0

3 years ago

Create a circle such that its center is point A and B is a point on the circle. Capture the image, and paste or insert it in the

Whitepunk [10]

Answer: need help as well

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Alchen [17]

I = PRT where I= interest, P = principal (money invested), R = interest rate, T = time in years

1260 = (6000)(R)(3)
1260 = 18000R
R = 0.07, or 7%

4 0

3 years ago

8x^3+2x^2-8 estimate the relative maxima and relative minima

DIA [1.3K]

Compute the derivative:

$\dfrac{\mathrm d}{\mathrm dx}\bigg[8x^3+2x^2-8\bigg]=24x^2+4x$

Set equal to zero and find the critical points:

$24x^2+4x=4x(6x+1)=0\implies x=0,-\dfrac16$

Compute the second derivative at the critical points to determine concavity. If the second derivative is positive, the function is concave upward at that point, so the function attains a minimum at the critical point. If negative, the critical point is the site of a maximum.

$\dfrac{\mathrm d^2}{\mathrm dx^2}\bigg[8x^3+2x^2-8\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[24x^2+4x\bigg]=48x+4$

At $x=0$ , the second derivative takes on the value of $4$ , so the function is concave upward, so the function has a minimum there of $-8$ .

At $x=-\dfrac16$ , the second derivative is $-4$ , so the function is concave downward and has a maximum there of $-\dfrac{431}{54}$ .

6 0

3 years ago

Given f(x) = x² + 4x - 3, find f(-3)<br> O -3<br> O -6<br> O 0<br> O 18

Nitella [24]

Answer:

f(-3) = -6

Step-by-step explanation:

f(x) = x^2 + 4x - 3

f(-3) means to put -3 in place of x and then do the calculation.

f(-3)

= (-3)^2 + 4(-3) - 3

= 9 - 12 - 3

= -3 - 3

= -6

First square -3, its 9. Then multiply -3 and 4, that's -12. Then add everything.

f(-3) = -6

3 0

2 years ago