Tomas used incorrectly the rule of signs, the expression should be simplified as follows:
-2.6 + (-5.4)
-2.6 -5.4 = 8
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What mistake did Tomas likely make?</h3>
Here Tomas wants to perform an addition between two numbers:
-2.6 + (-5.4)
And the outcome that Tomas gets is:
-2.6 + (-5.4) = 2.8
Here his mistake seems to bee that he thought the second number was a positive number, and he solved the operation:
-2.6 + 5.4
So, he used wrong the rule of signs.
Remember that the rule of signs says that:
(-)*(+) = (+)*(-) = (-)
Using that, we can rewrite the original expression:
-2.6 + (-5.4)
to:
-2.6 - 5.4 
Solving that, we get:
-2.6 - 5.4 = -8
Which is the outcome that Tomas would have gotten if he had used correctly the rule of signs.
If you want to learn more about the rule of signs:
brainly.com/question/13333620
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Answer:
Step-by-step explanation:
 
        
             
        
        
        
Hello there! The missing y-values are 12, 14, and 16. 
Given all our x-values and two additional y-values, we can see that multiplying the x-value by 2 gives us the y-value. This is shown when x is 5 and 9, because multiplying 5 by 2 gave us 10, and multiplying 9 by 2 gave us 18. Because of this rule, we can multiply each given x-value by 2 to receive our y-value. Once solving, we also notice that the y-values all add by 2 to get the next factor as the data number increases. Hope this helps!
        
             
        
        
        
Apply to Row 2 : Row 2 + Row 1
2x + 2y + 3z = 0
y + 4z = -3
2x + 3y + 3z = 5
Apply to Row 3: Row 3 - Row 1
2x + 2y + 3z = 0
y + 4z = -3
y = 5
Apply to Row 3: Row 3 - Row 2
2x + 2y + 3z = 0
y + 4z = -3
-4z = 8
Simplify rows
2x + 2y + 3z = 0
y + 4z = -3
z = -2
<em>Note that the matrix is in echelon form now. The next steps are for back substitution.</em>
Apply to Row 2: Row 2 - 4 Row 3
2x + 2y + 3z = 0
y = 5
z = -2
Apply to Row 1: Row 1 - 3 Row 3
2x + 2y = 6
y = 5
z = -2
Apply to Row 1: Row 1 - 2 Row 2
2x = -4
y = 5
z = 2
Simplify the rows 
<u>x = -2</u>
<u>y = 5</u>
<u>z = -2</u>
 
        
             
        
        
        
Answer:
Hello! May I ask what "Desmos" is??
Step-by-step explanation: