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AnnZ [28]
3 years ago
15

A race organizer brought 24 gallons of sports drink for a race. How many quarts of sports drink did he buy?

Mathematics
2 answers:
pav-90 [236]3 years ago
8 0

96 qt

HOPE THIS WILL HELP U

maks197457 [2]3 years ago
4 0
24 gallons is 96 quarts. The answer is C.
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If the true mean is 50 and we reject the hypothesis that μ = 50, what is the probability of Type II error? Hint: This is a trick
Komok [63]

Answer:

Zero

Step-by-step explanation:

Given that:

the true mean is 50 and we reject the hypothesis that μ = 50

The probability of the Type II error will be zero, given that we reject the null hypothesis. This has nothing to do with if it is true or false.

Type II error is occurs when you accept a false null hypothesis. The probability of this error is denoted by beta which relies on sample size and population variance.

The probability of rejecting is equal to one minu beta. i.e it is the researchers goal to reject a false null hypothesis.

8 0
3 years ago
The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
melamori03 [73]

Answer:

0 ft < w ≤ 7 ft

Step-by-step explanation:

A=wl,  where w, l >0

A≤175 ft²

l= w+18

w(w+18)≤175

w²+18w-175≤0

zeros of are -25 and 7

(w + 25)*(w - 7) ≤ 0

w+25≤0, w-7≥0 ⇒ w ⊂ ∅

w+25≥0, w-7≤0 ⇒ -25 ≤ w ≤ 7,

as w>0, we have answer: 0 < w ≤ 7

4 0
3 years ago
Which choice could be the equation of a line parallel to the line represented by this equation? y=7/4x - 6
stealth61 [152]
The answer is c, because it is the same line, just higher.
7 0
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If the pottery maker works 6 hours each day,how long does it take to make 1 vase
nlexa [21]
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6 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
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