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g100num [7]
4 years ago
13

A group of words that's missing a subject, a verb, or a complete thought is called a(n)

Mathematics
1 answer:
Sedbober [7]4 years ago
5 0
The answer is A. Sentence fragment. Hope this helps. (ノ◕ヮ◕)ノ*:・゚✧ 

You might be interested in
Select all expressions that are equivalent to x2 - 4x – 32.
ELEN [110]

Answer:

(x + 4)(x – 8)

Step-by-step explanation:

1. (x – 16)(x + 2)

x² - 2x - 16x - 32

x² - 18x - 32

2. (x + 2)(x – 16)

x² - 16x + 2x - 32

x² - 14x - 32

3. (2 – )(x + 4)

2x + 8

4. (x + 8)(x – 4)

x² - 4x + 8x - 32

x² + 4x - 32

5. (x + 4)(x – 8)

x² - 8x + 4x - 32

x² - 4x - 32

6. (x – 4)(x+8)

x² + 8x - 4x - 32

x² + 4x - 32

8 0
3 years ago
a purse contains ₹550 notes of denomination of ₹10 and ₹50 if the number of rupees 50 notes is one less than of ₹10 notes then f
12345 [234]

Answer:

  9

Step-by-step explanation:

Let x represent the number of ₹50 notes. Then the number of ₹10 notes is (x+1) and the total value of all notes is ...

  ₹50·x + ₹10·(x+1) = ₹550

  ₹60·x = ₹540 . . . . . . . . . . . . subtract ₹10 and collect terms

  x = 9 . . . . . . . . . . . . . . divide by ₹60

The number of ₹50 notes is 9.

7 0
2 years ago
Read 2 more answers
3x-8=3(x-4)+1 plz plz help me fast is it infinite or no or one solution
Gemiola [76]

Answer:

no solution

Step-by-step explanation:

solve the equation

3x - 8 = 3(x-4) + 1    

3x - 8 = 3x - 11

3x + 3 = 3x

x + 3 = x

A number x plus 3 cannot equal a number x.        

5 0
3 years ago
Read 2 more answers
The sum of outer angles of a polygon is twice the sum of inner angles. How many sides does it have?
atroni [7]
<h2><em><u>6</u></em></h2><h2><em>The sum of the interior angles of a polygon is twice the sum of its exterior angles. Therefore, by solving we get n=6 sides</em></h2><h2><em>HOPE IT HELPS </em></h2><h2><em>THANK YOU </em></h2><h2><em></em></h2>
6 0
3 years ago
Read 2 more answers
Let f(x) = 4x2 + x + 1 and g(x) = x2 – 2
Juli2301 [7.4K]
To find  g (f(x))  you  should  substitute  "4x^2+x+1"   to  "x"  of  g(x)  function. You'll havew:

g(f(x))= (4x^2+x+1)^2-2=\\ \\ =(4x^2+x)^2 +2 \cdot (4x^2+x) \cdot 1 +1^2-2= \\ \\ = 16x^4+8x^3+x^2+8x^2+2x+1-2= \\ \\ = 16x^4+8x^3+9x^2+2x-1

To count (4x^2+x+1)^2  Just  assume  ( [4x^2+x] + 1)^2   and  use the (a+b)^2=a^2+2ab+b^2  formula, where a=4x^2+x  and  b=1
7 0
3 years ago
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