The sum of outer angles of a polygon is twice the sum of inner angles. How many sides does it have?

2 answers:

6 0

<h2><em><u>6</u></em></h2><h2><em>The sum of the interior angles of a polygon is twice the sum of its exterior angles. Therefore, by solving we get n=6 sides</em></h2><h2><em>HOPE IT HELPS </em></h2><h2><em>THANK YOU </em></h2><h2><em></em></h2>

yarga [219]2 years ago

3 0

Answer:

3 sides

Step-by-step explanation:

sum of exterior angles for all polygons is 360°

sum of interior angles for a polygon can be found by using the formula:

(n - 2) · 180° where 'n' is the number of sides

'sum of outer angles' = 360

'twice the sum of inner angles' = 2n

360 = 2n

n = 180

a three-sided polygon (triangle) has 180 degrees

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Two 6-sided dice are rolled. what is the probability that the sum of the two numbers on the dice will be greater than 9?

AVprozaik [17]

What combination of numbers are needed in order to get a sum of 9?
It can be:
• First die is 6 , second die is 3
• First die is 3 , second die is 6
• First die is 4 , second die is 5
• First die is 5 , second die is 4

How many possible combinations are made? Yep, 4 possible combinations.

Recall the formula for probability
$Probability = \frac{Number of desired outcomes}{Number of all possible outcomes}$

There are 4 desired number of outcomes.
How about the total possible outcomes?
• How many numbers are possible to appear when the first die is rolled?
Answer: 6
• What about the second die?
Answer: Also 6
• Therefore, total possible outcomes = 6 * 6 = 36 outcomes

You can now solve for the probability.

$Probability = \frac{4}{36} = \frac{1}{9}$ or approximately 11.11%