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4 years ago

I would really appreciate help

Mathematics

1 answer:

alexira [117]4 years ago

5 0

Check your y-intercept on the graph, it is at 3. Now go up two units and then move three units to the right you will see that it lands on a point. This is called rise/run. The shading goes above the line so that means you will use this symbol: >. Also it is a dotted line. So your inequality would be:
y > 2/3x + 3
I hope this helps love! :)

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Who can tutor me for free

krok68 [10]

Answer:

Do not ask for free tutoring (Nobody will really do it)

Step-by-step explanation:

Just use Brainly! Ask for questions and explanations and do what you can to get your work done. After that if you need further help then ask a parent/guardian/sibling or someone you know for help and if that doesn't work then come back to this. Hope this helps.

4 0

3 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame

lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678$

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{207.9 - 208}{0.1678}$

$Z = -0.6$

$Z = -0.6$ has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0

3 years ago

James estimated the total cost of groceries to be $50. The actual cost of the groceries is $65. What is the percent error? Round

Alex777 [14]

To get percent error you take actual-predicted and divide by the actual then multiply by 100 to get the percent.

65-50=15

15/60=0.25

0.25 times 100 =25%

7 0

3 years ago

Read 2 more answers

In Nebraska on I-80, the speed limit is 75 mph. How long would it take you to travel 525 miles in Nebraska on I-80 if you went t

julia-pushkina [17]

the answer to your question is 7 hours just keep adding 75 together

3 0

3 years ago

To make 4.5 cups of fruity granola, the recipe calls for 1.5 cups of raisins, 1 cup of granola, and 2 cups of blueberries. If yo

Levart [38]

Answer:

you need 6 cups of raisins, 4 cups of granola and 8 cups of blueberries.

Step-by-step explanation:

Step 1: Find how much raisins are needed

For 4.5 cups of fruity granola, we need 1.5 cups of raisins

For 18 cups of fruity granola, we need y cups of raisins

4.5 : 1.5

18 : y

Cross multiply

4.5y = 1.5 x 18

y = 27/4.5

y = 6 cups of raisins

Step 2: Find how much granola is needed

For 4.5 cups of fruity granola, we need 1 cup of granola

For 18 cups of fruity granola, we need y cups of granola

4.5 : 1

18 : y

Cross multiply

4.5y = 18

y = 4 cups of granola

Step 3: Find how much blueberries are needed

For 4.5 cups of fruity granola, we need 2 cups of raisins

For 18 cups of fruity granola, we need y cups of blueberries

4.5 : 2

18 : y

Cross multiply

4.5y = 2 x 18

y = 36/4.5

y = 8 cups of blueberries

Therefore, in order to make 18 cups of fruity granola, you need 6 cups of raisins, 4 cups of granola and 8 cups of blueberries.

5 0

4 years ago