Answer:
When I solved it I got y ≥ -2|x + 1| + 3
Hope this helps. Sorry I am so late at answering this.
Answer:
Step-by-step explanation:

Answer:
c
Step-by-step explanation:
If you put one side into your calculator the the other will be come otut
Answer:
(3x + 5)(2x + 3)
Step-by-step explanation:
