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Fiesta28 [93]
3 years ago
8

Write an application that accepts a word from a user and converts it to Pig Latin. If a word starts with a consonant, the Pig La

tin version removes all consonants from the beginning of the word and places them at the end, followed by ay. For example, cricket becomes icketcray. If a word starts with a vowel, the Pig Latin version is the original word with ay added to the end. For example, apple becomes appleay. If y is the first letter in a word, it is treated as a consonant; otherwise, it is treated as a vowel. For example, young becomes oungyay, but system becomes ystemsay. For this program, assume that the user will enter only a single word consisting of all lowercase letters.
Computers and Technology
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

Written in Python

word = input("Word: ")

if(word[0]=='a' or word[0]=='e' or word[0]=='i' or word[0] =='o' or word[0]=='u'):

     print(word+"ay")

else:

     a = word[1:]

     print(a+word[0]+"ay")

Explanation:

<em>The program was written in Python and I've added the explanation as an attachment; where I used comments as explanations</em>

Download txt
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Answer:

B. Can't stop things from doing wrong.

Explanation:

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Write a program that calculates and displays the amount ofmoney available in a bank account that initially has $8000 deposited i
Leviafan [203]

Answer:

Written in Python

import math

principal = 8000

rate = 0.025

for i in range(1, 11):

    amount = principal + principal * rate

    principal = amount

    print("Year "+str(i)+": "+str(round(amount,2)))

Explanation:

This line imports math library

import math

This line initializes principal amount to 8000

principal = 8000

This line initializes rate to 0.025

rate = 0.025

The following is an iteration from year 1 to 10

for i in range(1, 11):

    This calculates the amount at the end of the year

    amount = principal + principal * rate

    This calculates the amount at the beginning of the next year

    principal = amount

    This prints the calculated amount

    print("Year "+str(i)+": "+str(round(amount,2)))

6 0
4 years ago
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
c++ Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins wi
Margaret [11]

Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string>  //header file

#include <vector>  //header file

//name space

using namespace std;

//main function

int main() {

  vector<string> word; //set variable

  vector<int> c;  //set variable

  int s, counts = 0; //set variable

  string strng;  //set variable

  cout<<"Enter the size of string: "; //print message

  cin >> s; //get input

  cout<<"Enter the string: "; //print message

  for(int i = 0; i < s; ++i) {  //set for loop

     cin >> strng; //get input

     word.push_back(strng);

  }

  for(int i = 0; i < s; ++i) { //set for loop

         counts = 0;

         for(int j = 0;j<word.size();j++){ //set for loop

       if(word[j] == word[i]){ //set if statement

          counts++; //increament in counts

       }        

     }

      c.push_back(counts);

  }

  for(int i = 0; i < s; ++i) {

      cout << word[i] << " " << c[i] << endl;//print result

  }

  return 0;

}

<u>Output</u>:

Enter the size of string: 2

Enter the string: hello  sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

  • Then, we set two vector type variables first one is string variable "word" and the second one is integer variable "c".
  • Then we set two integer variable "s" and "counts" and variable "counts" assign to 0.
  • Then, we get input from the user in variable "s" for the length of the loop.
  • Then, we set for the loop inside it, we get input in the variable "strng" from the user.
  • Then, we set the for loop for count the string repetition if any word comes again in the string then the value of count will increase.
  • Finally, we set for a loop to print the result.
4 0
3 years ago
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