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ivanzaharov [21]
2 years ago
7

London 8 meters long 4 meters wide and 2 meters deep what is the volume

Mathematics
1 answer:
kvasek [131]2 years ago
8 0
Volume = 8 * 4 * 2  = 64 m^3 Answer
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A canister is dropped from a helicopter 500m above the ground. Its parachute does not open, but the canister has been designed t
solmaris [256]

Answer:

The impact speed 98.995 m/s is less than 100 m/s and the canister will not burst.

Step-by-step explanation:

A function<em> F</em> is called an antiderivative of <em>f</em> on an interval <em>I</em> if F'(x) = f(x) for all x in <em>I.</em>

Recall that if the object has position function s=f(t), then the velocity function is v(t)=s'(t). This means that the position function is an antiderivative of the velocity function. Likewise, the acceleration function is a(t)=v'(t), so the velocity function is an antiderivative of the acceleration.

An object near the surface of the earth is subject to a gravitational force that produces a downward acceleration denoted by g. For motion close to the ground we may assume that g is constant, its value being about 9.8 \:{\frac{m}{s^2}}.

We know that the acceleration due to gravity is given by

a(t)=-9.8

and the antiderivative is velocity

v(t)=\int a(t)\,dt\\v(t)=\int -9.8\,dt\\v(t)=-9.8t +C

We know that the canister was dropped, so the initial velocity at t = 0 is zero, this fact let us know the value of C.

v(0)=9.8(0)+C\\C=0

The antiderivative of velocity is the position

s(t)=\int v(t) \, dt\\s(t)=\int -9.8t \, dt\\s(t)=-4.9t^2+C

To find the value of the constant C, we know that the height was 500 m at t  = 0, this means s(0)=500

500=-4.9(0)^2+C\\C=500

s(t)=-4.9t^2+500

Using the fact that at the time of impact the height s(t) is zero we can compute the total time of the fall:

s(t)=-4.9t^2+500=0\\\\-4.9t^2=-500\\\\t^2=\frac{5000}{49}\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\t=\sqrt{\frac{5000}{49}},\:t=-\sqrt{\frac{5000}{49}}

A negative time does not make sense, so we only take as a possible solution

t=\sqrt{\frac{5000}{49}}=\frac{50\sqrt{2}}{7}\approx 10.102

Now the final velocity is

v(\frac{50\sqrt{2}}{7})=-9.8(\frac{50\sqrt{2}}{7})\approx -98.995

The impact speed 98.995 m/s is less than 100 m/s and the canister will not burst.

5 0
3 years ago
Is x^ 2 - 16 the difference between two squares? Why?
bearhunter [10]

Answer:

x1= -4

x2 = 4

Step-by-step explanation:

Set the equation equal to zero

x2 − 16 = 0

then

(x + 4)(x − 4) = 0

(x+4)= 0 which is equal to -4

and

(x-4)= 0 equals 4

3 0
3 years ago
Read 2 more answers
Drag the sliders.<br> Which slider creates scale copies of the shape?
fenix001 [56]
You would have to drag the sliders and see which one just turns bigger and whichever that one is, is correct
7 0
1 year ago
Find 3 consecutive even integers if their sum decreased by 10 equals -22
Orlov [11]
Three consecutive even integers can be represented by x, (x+2), and (x+4).

(x + (x + 2) + (x + 4)) - 10 = -22   Get rid of the parentheses
    x + x + 2 + x + 4 - 10 = -22   Combine like terms (x + x + x) and (2 + 4 - 10)
                               3x - 4 = -22   Add 4 to both sides
                                    3x = -18   Divide
                                      x = -6
Check you work.

x = -6
x + 2 = -4
x + 4 = -2

(-6 - 4 - 2) - 10 = 22
-12 - 10 = -22

So, your three integers are -6, -4, and -2 .
6 0
3 years ago
The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
zimovet [89]

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

5 0
2 years ago
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