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3 years ago

I need help with a maths question please answer only if you know and not links

Mathematics

1 answer:

kotegsom [21]3 years ago

8 0

Answer:

x³/4z²

Step-by-step explanation:

Invert and multiply:

48x^5y²/12z^5 x z³/16x²y²=

(48x^5y²)(z³)/(16x²y²)(12z^5)

the y² cancel out

48÷16=3 (on top)

x^5÷x²=x³

12z^5/z³=z²(on bottom)

This leaves a 3x³ on top and 12z² on the bottom. 3÷12=4 (on bottom):

3x³/12z²

x³/4z²

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The value of U.S exports to China increased from $1480 million in 2011 to $2768 million

aliya0001 [1]

The percentage of increase was 87.027... %

<em><u>Explanation</u></em>

The value of U.S exports to China increased from $1480 million to $2768 million.

Suppose, the percentage of increase is $x\%$

So, <u>the amount of increase</u> = $x\%$ of 1480 $=1480*\frac{x}{100}=14.8x$

Thus, the equation will be......

$14.8x= 2768-1480\\ \\ 14.8x=1288\\ \\ x= \frac{1288}{14.8}=87.027....$

So, the percentage of increase was 87.027... %

7 0

4 years ago

Juan purchased an antique that had a value of \$200$200dollar sign, 200 at the time of purchase. Each year, the value of the ant

garri49 [273]

Answer:

<h2>The value of a is $(\frac{11}{10} )^{222}$ .</h2>

Step-by-step explanation:

At the time of purchase, the value of the antique is $200.

After one year the value will increase 10%.

Hence, after one year, the value of the antique will be $\frac{110}{100} \times200$ = 220.

Similarly, after two year, the value will be $200\times (\frac{110}{100} )^{2}$ .

Thus, 222 years after purchase, the value of the antique will be $200\times (\frac{110}{100} )^{222} = 200\times (\frac{11}{10} )^{222}$ .

5 0

3 years ago

Select the values that make the inequality y≥2y≥2 true.

ExtremeBDS [4]

9514 1404 393

Answer:

{2, 2.001, 2.01, 2.1, 3, 5, 7, 10}

Step-by-step explanation:

The symbol ≥ means "greater than or equal to", so any values 2 or greater will make the inequality true. From your list, those are ...

2 2.001 2.01 2.1 3 5 7 10

3 0

3 years ago

The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster is 0.608 meter lo

Mamont248 [21]

Answer:

Gila Monster is 1.54 times that of Chuckwalla.

Step-by-step explanation:

Given:

Average Length of Gila Monster = 0.608 m

Average Length of Chuckwalla = 0.395 m

We need to find the number of times the Gila monster is as the Chuckwalla.

Solution:

Now we know that;

To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.

framing in equation form we get;

number of times the Gila monster is as the Chuckwalla = $\frac{0.608}{0.395} = 1.5392$

Rounding to nearest hundredth's we get;

number of times the Gila monster is as the Chuckwalla = 1.54

Hence Gila Monster is 1.54 times that of Chuckwalla.

5 0

4 years ago

Explain what step is incorrect pls help quick!?!??

AlekseyPX

Answer:

Step 1 (IM AM NOT SURE NOT MY FAULT IF ITS WRONG)

Step-by-step explanation:

4 0

3 years ago

I need help with a maths question please answer only if you know and not links​

I need help with a maths question please answer only if you know and not links