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Makovka662 [10]
3 years ago
7

In a clinical​ trial, 21 out of 700 patients taking a prescription drug complained of flulike symptoms. Suppose that it is known

that 1.5​% of patients taking competing drugs complain of flulike symptoms. Is there sufficient evidence to conclude that more than 1.5​% of this​ drug's users experience flulike symptoms as a side effect at the alpha equals 0.05 level of​ significance?
Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

I don't knowhhhdchdhgdcsjfjdjcfjc

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A digital watch cost$11.75, what is the tax rate at $3.75%
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4 0
3 years ago
A real estate agent has 1212 properties that she shows. She feels that there is a 50P% chance of selling any one property during
forsale [732]

Answer:

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The probability of a property being sold is independent of any other property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

12 properties

This means that n = 12

She feels that there is a 50% chance of selling any one property during a week.

This means that p = 0.5

Compute the probability of selling no more than 6 properties in one week.

This is:

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934

P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.2256

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 + 0.1934 + 0.2256 = 0.6127

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

6 0
3 years ago
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