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Answer:
0.375 feet-lb
Step-by-step explanation:
We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.
We can represent our given information as:
We will use Hooke's Law to solve our given problem.
Substituting this value in our integral, we will get:
Using power rule, we will get:
We know that 6 inches is equal to 0.5 feet.
Work needed to stretch it beyond 6 inches beyond its natural length would be
Using power rule, we will get:
Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.