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zavuch27 [327]
3 years ago
8

What is the midpoint of AB?

Mathematics
1 answer:
dem82 [27]3 years ago
3 0

It looks like Point G is correct

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Write a cubic function whose graph passes through the points (-4,0)(4,0)(0,6) and (2,0)
gulaghasi [49]

Answer: 3/16(x+4)(x-4)(x-2)

Step-by-step explanation:

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A student wrote a number pattern such that each number is 3 more that 4 times the previous number. What is the sixth term in the
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Start with 1.
1st number = 1
2nd number = 1 * 4 + 3 = 7
3rd number = 7 * 4 + 3 = 31
4th = 31 * 4 + 3 = 127
5th = 127 * 4 + 3 = 511
Which means the 6th = 511 * 4 + 3, which is 2047.
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Original price of a phone: $129.99<br> Tax: 2%
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$132.59 is the answer

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To assess the precision of a laboratory scale, we measure a block known to have a mass of 1 gram. we measure the block n times a
vlada-n [284]
<span>n = 5 The formula for the confidence interval (CI) is CI = m ± z*d/sqrt(n) where CI = confidence interval m = mean z = z value in standard normal table for desired confidence n = number of samples Since we want a 95% confidence interval, we need to divide that in half to get 95/2 = 47.5 Looking up 0.475 in a standard normal table gives us a z value of 1.96 Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula 0.0001 = z*d/sqrt(n) Substitute the value z that we looked up, and get 0.0001 = 1.96*d/sqrt(n) Substitute the standard deviation that we were given and 0.0001 = 1.96*0.001/sqrt(n) 0.0001 = 0.00196/sqrt(n) Solve for n 0.0001*sqrt(n) = 0.00196 sqrt(n) = 19.6 n = 4.427188724 Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>
8 0
3 years ago
Four different towns in the same state grew in size due to a revitalization effort. The population of town A grew from 22,000 to
Savatey [412]

Answer:

Town C.

Step-by-step explanation:

Average change of population with time for town A = \frac{24,500 - 22,000}{4} = \frac{2,500}{4} = 625

Average change of population with time for town B = \frac{34,770 - 31,200}{6} = \frac{3,570}{6} = 595

Average change of population with time for town C = \frac{22,000 - 18,000}{5} = \frac{4,000}{5} = 800

Average change of population with time for town D = \frac{34,100 - 32,000}{3} = \frac{2,100}{3} = 700

Town C had the greatest average change in population over time (800/yr).

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3 years ago
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