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4 years ago

How much interest would a bond (1,000 shares) of RMx pay each year?

Mathematics

2 answers:

Aliun [14]4 years ago

8 0

B and E for sure 6+g

nekit [7.7K]4 years ago

4 0

Answer:

a and e

Step-by-step explanation:

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Why are these two angles congruent?

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What angels? You need to show a picture :)

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3 years ago

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Which polynomial identity will prove that 64+27=91

Kipish [7]

8^3+3^3

27=3*3*3
64=8*8*8

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4 years ago

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The students in the cooking club brought sugar to class they each brought 3,4,5and 6cups of sugar respectively they divided the

geniusboy [140]

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if there is 4 students then each student gets about 4 1/2 cups of sugar.

Step-by-step explanation:

3+4+5+6=18

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4 years ago

Question 1 ( point) A 64g sample of Germanium-66 is left undisturbed for 12.5 hours. At the end of that period, only 2.0g remain

iVinArrow [24]

Answer:

2.5 half-lives

Step-by-step explanation:

Find $t_{h}$ in $N(t)=N_{0}e^{-kt}$ given $N(t) = 2, N_{0} =64,t=\frac{25}{2}$

$N(t)$ is the amount after the time $t$ , $N_0$ `is the initial amount, $t_{h}$ is the half-life

We know that after half-life there will be twice less the initial quantity:

$N(t_{h})=\frac{N_{0} }{2}=N_{0}e^{kt_{h} }$ .

Simplifying gives $\frac{1}{2} =e^{-kt_h} or k = -\frac{In(\frac{1}{2}) }{t_{h} } .$

Plugging this into the initial equation, we obtain that $N(t)=N_{0}e^\frac{In(\frac{1}{2}) }{t_{h} }$ or $N(t)= N_{0} (\frac{1}{2})^\frac{t}{t_h}.$

Finally, just plug in the given values and find the unknown one.

From $2=64(\frac{1}{2})^\frac{\frac{25}{2} }{t_h}$ , we have that $t_h$ = $\frac{25 In (2)}{2 In (32)\\}$

So you should get: $t_{h} =\frac{25 In (2)}{2 In (32)\\}=2.5.$

<h2><u>MARK ME AS BRAINLIEST IF YOU WISH</u></h2><h2><u /></h2>

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3 years ago

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I’ll mark as BRANLIEST!!

Helen [10]

Answer:

Take the sum of two to the power three and four away from ten and divide it by one less than three

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