
![\bf \stackrel{\textit{multiplying both sides by LCD of 3}}{3(y+5)=3\left[ \cfrac{5}{3}(x-3) \right]}\implies 3y+15=5(x-3) \\\\\\ 3y+15=5x-15\implies -5x+3y=-30\implies \stackrel{\textit{multiplying by -1}}{5x-3y=30}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20LCD%20of%203%7D%7D%7B3%28y%2B5%29%3D3%5Cleft%5B%20%5Ccfrac%7B5%7D%7B3%7D%28x-3%29%20%5Cright%5D%7D%5Cimplies%203y%2B15%3D5%28x-3%29%0A%5C%5C%5C%5C%5C%5C%0A3y%2B15%3D5x-15%5Cimplies%20-5x%2B3y%3D-30%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20by%20-1%7D%7D%7B5x-3y%3D30%7D)
bearing in mind the standard form uses all integers, and the x-variable cannot have a negative coefficient.
Answer:
11. x=15 , 12. x=-16, 13 x is greater than or equal to 15 , 14 x=-3 , 15 x=-3, 16 x=15/2 , 17 x is greater than is equal to -4, 18: x is greater than -11
Step-by-step explanation:
11. 4x+15=75
subtract 15
4x=60
divide
x=15
12. 2x = -32 (subtract 13 from each side)
divide
x=-16
13. multiply each side by
-3/2
x is greater than or equal to 15
14. -3x -18 + 5 = -4
isolate x
-3x=9
x=-3
15. -5x-30 +5=-10
isolate x
-5x = 15
x= -3
16. 2x + 16 = 6x - 14
isolate x
4x = 30
x= 15/2
17 isolate x
x is greater than is equal to -4
18. isolate x
x is greater than -11
Answer:
Look that the coordinates and trace those points to a corresponding number on the x or y axis. Then write the first number in the coordinate in the x value and the second number for the y value, repeat the process for the rest of the points.
Step-by-step explanation:
Given:
Consider the equation is:

Some steps of the solution are given.
To find:
The next step of the solution.
Solution:
Step 1: The given equation is:

Step 2: Simplifying right hand side.

Step 3: Simplifying left hand side.

These steps are already given. So, the next step is:
Step 4: Subtracting 3 from both sides.

Therefore, the correct option is (b).