Hello:
<span>(4x-2)(6x+ 7)=24x²+28x-12x-14
= 24x²+16x-14
</span><span>in the standard form : ax²+bx+c a = 24 b=16 c=-14</span>
Answer:
8
Step-by-step explanation:
Given:
Total money Jervane can spend = $20.
Cost of a coffee = $3.
Cost of a donut = $2.
To find: Maximum number of donuts Jervane can buy.
Solution:
Let the number of donuts she can buy be
.
She wants to spend no more than $20 in total.
So,
![3+2x\leq 20](https://tex.z-dn.net/?f=3%2B2x%5Cleq%2020)
![\Rightarrow 2x\leqslant 20-3](https://tex.z-dn.net/?f=%5CRightarrow%202x%5Cleqslant%2020-3)
![\Rightarrow 2x\leqslant 17](https://tex.z-dn.net/?f=%5CRightarrow%202x%5Cleqslant%2017)
![\Rightarrow x\leqslant \frac{17}{2}](https://tex.z-dn.net/?f=%5CRightarrow%20x%5Cleqslant%20%5Cfrac%7B17%7D%7B2%7D)
![\Rightarrow x\leqslant 8 \frac{1}{2}](https://tex.z-dn.net/?f=%5CRightarrow%20x%5Cleqslant%208%20%5Cfrac%7B1%7D%7B2%7D)
As the number of donuts can only be a natural number.
Hence, the maximum number of donuts that Jervane can buy are 8.
I'm not sure if this is correct but (x + 9) • (x - 9)
A=48
b=144
c=-84
First, you simplify the second equation by multiplying 6 to 2x and 6 to 7. Then, you get the two equations, (4x-2) times (12x+42). You then use the FOIL method, multiplying 4x to 12x, 4x to 42, -2 to 12x, then -2 to 42. Simplify. Then number before x squared is your a value, value before x is b, and the value without x is c.