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FromTheMoon [43]
3 years ago
5

The width of a rectangle is 9 cm. The perimeter is 40 cm. What is the length of the rectangle?

Mathematics
2 answers:
Anna35 [415]3 years ago
7 0

Answer:

it is 11 cm I think ✌because I did the math and got

11 cm hope this is right

Keith_Richards [23]3 years ago
6 0

Answer:

11

Step-by-step explanation:

2(l+w)

40= 2(9+x)

40= 18+2x

Subtract 18 from 40

22=2x

Divide 2x by itself and 22

11=x or x=11

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Simplify the expression <br> 5s+2s
AleksandrR [38]

Answer:

7s

Step-by-step explanation:

We can combine this because they are like terms.

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3 years ago
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1/4 + 1/2 +x=−3/4
masya89 [10]
Work from the left to right.
add 1/4 and 1/2 which would give you 3/4
then subtract 3/4 from both sides of the equal sign witch would give you
x=-3/2
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In this activity, you're going to write a SUMMARY paragraph for this lesson over Measuring and Graphing Motion. In your summary,
Alinara [238K]

Answer:

Answer

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6 0
3 years ago
PLEASE HELP !!!!!!!
N76 [4]

Answer:

(B) Time (min) 2 , 3 , 7 , 9

Temperature (°C) 60.6 , 64.3 , 79.1 , 86.5

Step-by-step explanation:

The rate of change is found by using the formula for slope:

m=\frac{y_2-y_1}{x_2-x_1}

For option A, this gives us

m =(64.4-61.0)/(3-2) = 3.4/1 = 3.4

This is not more than relationship A.

For option B, we have

(64.3-60.6)/(3-2) = 3.7/1 = 3.7

This is more than relationship A.

For option C, we have

(65.3-61.8)/(3-2) = 3.5/1 = 3.5

This is not more than relationship A.

For option D, we have

(64.6-61.0)/(3-2) = 3.6/1 = 3.6

This is not more than relationship A.

7 0
3 years ago
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A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil
erma4kov [3.2K]

Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

\frac{n_p}{n_s}=\frac{1}{1000}

5 0
3 years ago
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