Answer:
The number of large boxes is 55 and the number of small boxes is 70
Step-by-step explanation:
<u><em>The complete question is</em></u>
A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 50 pounds each, and the small boxes weigh 20 pounds each. There are 125 boxes in all. If the truck is carrying a total of 4150 pounds in boxes, how many of each type of box is it carrying?
Let
x ------> the number of large boxes
y -----> the number of small boxes
we know that
-----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The intersection point is (55,70)
therefore
The number of large boxes is 55 and the number of small boxes is 70
Angle 1 is a right angle =90 °
so 5x-85=90
5x=90+85
5x=175
x=35
Answer:
The ball will reach a height of 5 ft by the 4th time.
Step-by-step explanation:
The initial height of the ball is 40 ft, when it bounces from the floor once the height will be 20 ft, the second time it'll be 10 ft, and so on. The sequence that can represent the maximum height of the ball after each bounce is:
{40, 20, 10,...}
This kind of sequence is called a geometric progression, in this kind of progression the next number is related to the one before it by the product of a constant called ratio, in this case 1/2. To calculate a specific position in this sequence we only need the ratio and the first number, using the formula below:
a_n = a*r^(n-1)
Where n is the position we want to know, a is the first number and r is the ratio. In this case we have:
a_4 = 40*(1/2)^(4-1) = 40*(1/2)^3 = 40/8 = 5
The ball will reach a height of 5 ft by the 4th time.
Answer:
27 are blue C.
Step-by-step explanation:
