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jarptica [38.1K]
3 years ago
7

The perimeter of a scalene triangle is 14.5 cm. The longest side is twice that of the shortest sidd.which equation can be used t

o find the side lengths if the longest side meassures 6.2 cm.?
Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0
Let S, M, L represent the shortest, mid-length, and longest sides, respectively. You are given three bits of information.
.. S +M +L = 14.5 cm
.. L = 2S
.. L = 6.2 cm
You can use an equation something like this to find the middle-length side.
.. (6.2 cm)/2 +M +6.2 cm = 14.5 cm
.. M +9.3 cm = 14.5 cm . . . . . . . . . . . . . constant terms collected
.. M = 5.2 cm . . . . . . . . . . . . . . . . . . . . . subtract 9.3 cm

Now, you know the side lengths are 3.1 cm, 5.2 cm, 6.2 cm.
_____
You have not offered any choices for "which equation," so take your pick of those used here.
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b

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c

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Step-by-step explanation:

From the question we are told that

   The population mean is  \mu =  3 \  hours

   The standard deviation is  \sigma  =  1.4 \ hours

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

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        P(X  <  1.4) =  P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma}   )

Here \frac{X - \mu}{\sigma }  =  Z (The\ standardized\ value\ of\  X)

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     P(X  <  1.4) =  P(Z < -1.1429  )

From the z-table the value of  

        P(Z < -1.1429  )=0.12654

So     P(X  <  1.4) = 0.12654

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

        P(X  >  3.5) =  P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma}   )

        P(X >  3.5) =  P(Z > \frac{3.5 - 3.0}{1.4}   )

        P(X >  3.5) =  P(Z > 0.3571  )

From the z-table the value of  

        P(Z >0.3571  )=0.36051

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Answer:

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Hello There!

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