Answer:
Option C
Step-by-step explanation:
6x² +5x + 1
6x² + 3x + 2x + 1
3x(2x + 1) + 1(2x + 1)
(3x + 1)(2x + 1)
Answer:
a) 504
b) 56
c) 0.111
Step-by-step explanation:
Data provided in the question:
There are nine golf balls numbered from 1 to 9 in a bag
Three balls are randomly selected without replacement
a) 3-digit numbers that can be formed
= ![^nP_r](https://tex.z-dn.net/?f=%5EnP_r)
n = 9
r = 3
= ⁹P₃
= ![\frac{9!}{9!-3!}](https://tex.z-dn.net/?f=%5Cfrac%7B9%21%7D%7B9%21-3%21%7D)
= 9 × 8 × 7
= 504
b) 3-digit numbers start with the digit 1
= _ _ _
in the above 3 blanks first digit is fixed i.e 1
we and we have 8 choices left for the last 2 digits
Thus,
n = 8
r = 2
Therefore,
= 1 × ⁸P₂
= 1 × ![\frac{8!}{8!-2!}](https://tex.z-dn.net/?f=%5Cfrac%7B8%21%7D%7B8%21-2%21%7D)
= 1 × 8 × 7
= 56
c) Probability that the 3-digit number formed is less than 200
Now,
The number of 3-digit number formed is less than 200 will be the 3-digit numbers start with the digit 1 i.e part b)
and total 3-digit numbers that can be formed is part a)
therefore,
Probability that the 3-digit number formed is less than 200
= 56 ÷ 504
= 0.111
Well first of this makes sense because you need to make sure your rug will fit. So anyways, first lay your rug out on a flat surface, grab your yardstick, lay it on the rug to find the length and then the width. you then know the size of your rug(assuming its square). You can do the same thing in the room you want it in.
Answer:
answer is 38 yd
Step-by-step explanation:
area of square =1444 yd^2
z^2=1444 yd^2
z=
yd^2
z=38 yd
Hope this helps u!!
Answer:
0.28cm/min
Step-by-step explanation:
Given the horizontal trough whose ends are isosceles trapezoid
Volume of the Trough =Base Area X Height
=Area of the Trapezoid X Height of the Trough (H)
The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)
The Volume of water in the trough at any time
![Volume=\frac{1}{2} (b_{1}+4+2x)h X H](https://tex.z-dn.net/?f=Volume%3D%5Cfrac%7B1%7D%7B2%7D%20%28b_%7B1%7D%2B4%2B2x%29h%20X%20H)
![Volume=\frac{1}{2} (4+4+2x)h X 16](https://tex.z-dn.net/?f=Volume%3D%5Cfrac%7B1%7D%7B2%7D%20%284%2B4%2B2x%29h%20X%2016)
=8h(8+2x)
V=64h+16hx
We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles
x/h=1/4
4x=h
x=h/4
Substituting x=h/4 into the Volume, V
![V=64h+16h(\frac{h}{4})](https://tex.z-dn.net/?f=V%3D64h%2B16h%28%5Cfrac%7Bh%7D%7B4%7D%29)
![V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}](https://tex.z-dn.net/?f=V%3D64h%2B4h%5E2%5C%5C%5Cfrac%7BdV%7D%7Bdt%7D%3D%2064%5Cfrac%7Bdh%7D%7Bdt%7D%2B8h%20%5Cfrac%7Bdh%7D%7Bdt%7D)
h=3m,
dV/dt=25cm/min=0.25 m/min
![0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}](https://tex.z-dn.net/?f=0.25%3D%20%2864%2B8%2A3%29%20%5Cfrac%7Bdh%7D%7Bdt%7D%5C%5C0.25%3D88%5Cfrac%7Bdh%7D%7Bdt%7D%5C%5C%5Cfrac%7Bdh%7D%7Bdt%7D%3D%5Cfrac%7B0.25%7D%7B88%7D)
=0.002841m/min =0.28cm/min
The rate is the water being drawn from the trough is 0.28cm/min.