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just olya [345]
3 years ago
6

Thomas is constructing an inscribed regular hexagon for the circle shown. Point A will be one vertex of the hexagon. What step s

hould be completed next?
Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0
SET THE WIDTH OF THE COMPASS TO EQUAL AP
Anon25 [30]3 years ago
7 0

Answer:

Set the width of compass equal to length between center P and vertex A.

Step-by-step explanation:

Given a circle.

Thomas is constructing a regular hexagon inside the circle that means Thomas is constructing a polynomial  having 6 equal sides inside the circle.

Point A is one vertex which lies on circle as well as on hexagon and point P is the center of the circle.

As the side of regular hexagon = radius of hexagon or radius.

The step which should be taken is to set the length of compass equal to distance between the point A and P that means set the width of compass equal to AP

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Which fraction is equal to ⅛?<br> ⁴⁄₆ ⁴⁄₃₀ ²⁄₁₆
aliya0001 [1]

Answer:

2/16

Step-by-step explanation:

1/8 * 2/2 = 2/16

4 0
3 years ago
Read 2 more answers
Match the angles that are greater than 90° with their reference angles.
storchak [24]
For angles in first quadrant, the reference angle is itself. In second quadrant, the equation would be 180 - x where x is the measure of the angle. In third quadrant, x - 180. Lastly, in the fourth quadrant, the reference angle is 360 - x. From the second set of angles in the given, the reference angles are.
              (1) 135 ; RA = 180 - 135 = 45
              (2) 240; RA = 240 - 180 = 60
              (3) 270; RA = 90 (lies in the y - axis)
              (4) 330; RA = 360 - 330 = 30
7 0
3 years ago
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
2 years ago
Look at the equation 4x - 8.4 = 2x + 5. The terms 4x and 2x are like terms
xz_007 [3.2K]

In form ax + b = c: 2x - 8.4 = 5

Solution to equation: x = 6.7

Step-by-step explanation:

4x - 8.4 = 2x + 5

2x - 8.4 = 5

2x = 13.4

x = 6.7

3 0
2 years ago
Find d and the measure of each side of equilateral triangle KLM if KL=d+2, LM=12-d, and KM=4d-13
fiasKO [112]

Answer:

all sides are 7 units

Step-by-step explanation:

Since the triangle is equilateral then all 3 sides are equal in length

equate any 2 sides and solve for d

KL = LM

d + 2 = 12 - d ( add d to both sides )

2d + 2 = 12 ( subtract 2 from both sides )

2d = 10 ( divide both sides by 2 )

d = 5

KL = d + 2 = 5 + 2 = 7

LM = 12 - d = 12 - 5 = 7

KM = 4d - 13 = (4 × 5) - 13 = 20 - 13 = 7


4 0
3 years ago
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