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just olya [345]
3 years ago
6

Thomas is constructing an inscribed regular hexagon for the circle shown. Point A will be one vertex of the hexagon. What step s

hould be completed next?
Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0
SET THE WIDTH OF THE COMPASS TO EQUAL AP
Anon25 [30]3 years ago
7 0

Answer:

Set the width of compass equal to length between center P and vertex A.

Step-by-step explanation:

Given a circle.

Thomas is constructing a regular hexagon inside the circle that means Thomas is constructing a polynomial  having 6 equal sides inside the circle.

Point A is one vertex which lies on circle as well as on hexagon and point P is the center of the circle.

As the side of regular hexagon = radius of hexagon or radius.

The step which should be taken is to set the length of compass equal to distance between the point A and P that means set the width of compass equal to AP

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-19/2 divided by 38/5
slavikrds [6]

Answer:

-1.25

Step-by-step explanation:

The result can be shown in multiple forms. Exact Form: 385 38 5. Decimal Form: 7.6 7.6. Mixed Number Form: 735 7 3 5. 385 3 8 5 .

8 0
3 years ago
Given the function g(x) = 6(4)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
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3 years ago
Given a triangle with side lengths of 20 cm and 7 cm, what is a possible length of the third side?
ANEK [815]

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2 years ago
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The burges are moving across the country .Mr burges leaves 3 hours before mrs.burges. If he averages 50 mph and she averages 70
kirill [66]

10.5 hours

let t be time then distance travelled by both is

Mr Burges ⇔ d = 50t ( distance = speed × time )

Mrs Burges ⇒ d = 70(t - 3)

At the point of overtaking both will have travelled the same distance

equating their distance and solving for t

70(t - 3) = 50t

70t - 210 = 50t ( subtract 50t from both sides )

20t - 210 = 0 ( add 210 to both sides )

20t = 210 ( divide both sides by 20 )

t = 10.5 hours


4 0
3 years ago
The histogram shows the speeds of downhill skiers during a competition. Estimate the mean of the data set displayed in the histo
Ostrovityanka [42]

Answer:

≈50.6

Step-by-step explanation:

Not sure what precision level this problem is looking for, but for right-skewed distributions, we know that the mean is going to be pulled right and therefore the mean should be larger than the median. To a high confidence level, the mean should fall between 50 and 59, or in the third column.

If a single estimation is wanted, assume the values inside each column are uniformly distributed:

\displaystyle\\\widehat{\mu}=\frac{34.5\cdot 4+...+74.5\cdot 2}{4+9+4+4+2}\approx \boxed{50.6}

8 0
3 years ago
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