Explanation:
The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.
More formally, if V is the common vertex, and ...
- R is a point on one of the rays forming Angle 1
- S is a point on the ray that is the opposite of ray VR
- T is a point on the other ray forming Angle 1
- U is a point on the ray that is the opposite of ray VT
Then angle RVT and angle SVU are vertical angles.
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Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.
If the above conditions cannot be met, then the angles are not vertical angles.
Answer:
Step-by-step explanation:
There is an error in the question. The table does not show two linear functions. y₁ is a linear function, but y₂ is not a straight line. It makes a bend at (-6,1).
Line 1 goes through (-12,-3) and (0,5).
slope = (5-(-3))/(0-(-12)) = 2/3
y-intercept = 5
y₁ = (2/3)x + 5
Line 2 goes through (-12,-2) and (-6,1).
slope = (1-(-2))/(-6-(-12)) = 1/2
y₂ = (1/2)x + 4
(2/3)x + 5 = (1/2)x + 4
x = -6
y = (2/3)x + 5 = 1
Solution: (-6,1)
If your asking for a standard deck of cards the probability is 1/8
2.25 as a fraction is 2 1/4
Answer:
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Step-by-step explanation:
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