Answer: Company B charges $(15.5+0.12x) more for x miles than company A.
Step-by-step explanation:
Let x = Number of miles.
Total charge = Flat charge + (charge per mile) x (Number of miles)
Given:
For Company A ,
Flat charge= $45
Charge per mile = 11 cents = 0.11 [ 1 dollar = 100 cents i.e. 1 cent = 0.01 dollar]
Total charge = 45+0.01x
For Company B,
Flat charge= $60.50
Charge per mile = 13 cents = 0.13
Total charge = 60.50+0.13x
Difference in charge = Charge for company B - Charge for company A
= 60.50+0.13x-(45+0.01x)
= 15.5+0.12x
Hence, Company B charges $(15.5+0.12x) more for x miles than company A.
Answer:
paper clips = $1.85
index cards = $3.95
Step-by-step explanation:
Mark
12 paper clips = x
10 index cards = y
$61.70 total
Janice
15 paper clips = x
7 index cards = y
$55.40 total
12x + 10y = 61.70
15x + 7y = 55.40
*** you want to cancel out one of the letters
(12x + 10y = 61.70) * -7
(15x + 7y = 55.40) * 10
-84x -70y = -431.9
150x + 70y = 554.0
150x + 70y = 554.0
-84x -70y = -431.9
66x + 0 = 122.1
66x = 122.1
x = 122.1 ÷ 66
x = 1.85
plug it back in
15(1.85) + 7y = 55.40
27.75 + 7y = 55.40
7y = 55.40 - 27.75
7y = 27.65
y = 27.65 ÷ 7
y = 3.95
Answer:

Step-by-step explanation:
Anything set to equal <em>x</em> is considered an undefined <em>rate of change</em> [<em>slope</em>], which is a <em>vertical line</em>. This is not a function, since it flunks the <em>vertical line test</em>.
I am joyous to assist you anytime.
Answer:


Step-by-step explanation:
In single-variable calculus, the difference quotient is the expression
,
which its name comes from the fact that it is the quotient of the difference of the evaluated values of the function by the difference of its corresponding input values (as shown in the figure below).
This expression looks similar to the method of evaluating the slope of a line. Indeed, the difference quotient provides the slope of a secant line (in blue) that passes through two coordinate points on a curve.
.
Similarly, the difference quotient is a measure of the average rate of change of the function over an interval. When the limit of the difference quotient is taken as <em>h</em> approaches 0 gives the instantaneous rate of change (rate of change in an instant) or the derivative of the function.
Therefore,

