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tester [92]
3 years ago
14

Someone help me with my math homework?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

c

Step-by-step explanation:

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6. On Saturday, you bowl at Mar Vista Bowl, where renting shoes
olga_2 [115]

Answer:

3.50 +3.25 = 6.75

Sory If wrong :)

I hope This Help'S

6 0
3 years ago
A family wants to rent a car to go on vacation. Company A charges $45.50 and 11c per mile. Company B charges $60.50 and 13c per
Maslowich

Answer: Company B charges $(15.5+0.12x) more for x miles than company A.

Step-by-step explanation:

Let x = Number of miles.

Total charge = Flat charge + (charge per mile) x  (Number of miles)

Given:

For Company A ,

Flat charge= $45

Charge per mile =  11 cents  = 0.11   [ 1 dollar = 100 cents i.e. 1 cent = 0.01 dollar]

Total charge = 45+0.01x

For Company B,

Flat charge= $60.50

Charge per mile =  13 cents  = 0.13

Total charge = 60.50+0.13x

Difference in charge = Charge for company B -  Charge for company A

= 60.50+0.13x-(45+0.01x)

= 15.5+0.12x

Hence,  Company B charges $(15.5+0.12x) more for x miles than company A.

7 0
2 years ago
Mark bought 12 boxes of paper clips and 10 packages of index cards for a
Nata [24]

Answer:

paper clips = $1.85

index cards = $3.95

Step-by-step explanation:

Mark

12 paper clips = x

10 index cards = y

$61.70 total

Janice

15 paper clips = x

7 index cards = y

$55.40 total

12x + 10y = 61.70

15x + 7y   = 55.40

*** you want to cancel out one of the letters

(12x + 10y = 61.70) * -7

(15x + 7y   = 55.40) * 10

-84x -70y = -431.9

150x + 70y = 554.0

150x + 70y = 554.0

-84x -70y = -431.9

66x + 0 = 122.1

66x = 122.1

x = 122.1 ÷ 66

x = 1.85

plug it back in

15(1.85) + 7y   = 55.40

27.75 + 7y   = 55.40

7y   = 55.40 - 27.75

7y = 27.65

y = 27.65 ÷ 7

y = 3.95

8 0
3 years ago
(8,-3) and (8,4)<br> Linear functions
lesya692 [45]

Answer:

\displaystyle x = 8

Step-by-step explanation:

Anything set to equal <em>x</em> is considered an undefined <em>rate of change</em> [<em>slope</em>], which is a <em>vertical line</em>. This is not a function, since it flunks the <em>vertical line test</em>.

I am joyous to assist you anytime.

4 0
3 years ago
Find f(a), f(a+h), and<br> 71. f(x) = 7x - 3<br> f(a+h)-f(a)<br> h<br> if h = 0.<br> 72. f(x) = 5x²
Leni [432]

Answer:

71. \ \ \ f(a) \  = \  7a \ - \ 3; \ f(a+h) \  =  \ 7a \ + \ 7h \ - \ 3; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 7

72. \ \ \ f(a) \  = \  5a^{2}; \ f(a+h) \  =  \ {5a}^{2} \ + \ 10ah \ + \ {5h}^{2}; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 10a \ + \ 5h

Step-by-step explanation:

In single-variable calculus, the difference quotient is the expression

                                              \displaystyle\frac{f(x+h) \ - \ f(x)}{h},

which its name comes from the fact that it is the quotient of the difference of the evaluated values of the function by the difference of its corresponding input values (as shown in the figure below).

This expression looks similar to the method of evaluating the slope of a line. Indeed, the difference quotient provides the slope of a secant line (in blue) that passes through two coordinate points on a curve.

                                             m \ \ = \ \ \displaystyle\frac{\Delta y}{\Delta x} \ \ = \ \ \displaystyle\frac{rise}{run}.

Similarly, the difference quotient is a measure of the average rate of change of the function over an interval. When the limit of the difference quotient is taken as <em>h</em> approaches 0 gives the instantaneous rate of change (rate of change in an instant) or the derivative of the function.

Therefore,

              71. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{(7a \ + \ 7h \ - \ 3) \ - \ (7a \ - \ 3)}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{7h}{h} \\ \\ \-\hspace{4.25cm} = \ \ 7

               72. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{{5(a \ + \ h)}^{2} \ - \ {5(a)}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{{5a}^{2} \ + \ 10ah \ + \ {5h}^{2} \ - \ {5a}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{h(10a \ + \ 5h)}{h} \\ \\ \-\hspace{4.25cm} = \ \ 10a \ + \ 5h

4 0
2 years ago
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