Lets x and y are 2 accounts Paige invested
x account invested with annual interest rate 8.5%
y account invested with annual interest rate 10%
x + y =<span>15,250 so x = 15,250 - y
0.085x + 0.1y = </span><span>1,411.75
substitute </span>x = 15,250 - y into 0.085x + 0.1y = 1,411.75
0.085x + 0.1y = 1411.75
0.085(15,250 - y) + 0.1y = 1,411.75
1,296.25 - 0.085y + 0.1y = 1,411.75
0.015y = 115.5
y = 7,700
x = 15,250 - y
x = x = 15,250 - 7,700
x = 7,550
answer
$7,550 invested on account with annual interest rate 8.5%
$7,700 invested on account with annual interest rate 10%
Points 2,2
2=square root of 6-2
2=square root of 4
2=2
Yes point lies on graph
Points 6,0
0=square root of 6-6
0=0
Yes point lies on graph
Answer:
the first option - 48s + 4.75
Step-by-step explanation:
Answer:
The roots are
![x=\frac{1}{6} [3+ i\sqrt{3}]](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B6%7D%20%5B3%2B%20i%5Csqrt%7B3%7D%5D)
![x=\frac{1}{6} [3- i\sqrt{3}]](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B6%7D%20%5B3-%20i%5Csqrt%7B3%7D%5D)
Step-by-step explanation:
we have
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
Remember that
so
![x=\frac{1}{6} [3\pm i\sqrt{3}]](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B6%7D%20%5B3%5Cpm%20i%5Csqrt%7B3%7D%5D)
The roots are
