All categories

3 years ago

Geometry math question no Guessing and Please show work

Mathematics

1 answer:

Elan Coil [88]3 years ago

7 0

The Pythagorean Theorem states that for right triangles:

a^2=b^2+c^2

a= the hypotenuse

b and c equals the other two sides.

In this case we are given the hypotenuse so we can rearrange the equation to look like this b^2=a^2-c^2 (I subtracted c^2 from both sides). I know a and c so I can solve for b.

We get rid of a square by implementing a square root on both sides and get:

b=sqrt(a^2-c^2) .... b=sqrt( (sqrt(34))^2 - 3^2)

b= sqrt(25) ..... b=5

You might be interested in

G60°

mars1129 [50]

C
Should be 25.........

4 0

3 years ago

Does anyone know how to do this? I know it's easy but I forgot please help

kenny6666 [7]

Answer: 4

Step-by-step exzplanation: 20/360= X/72

360X= 1440

Divide by 360

X=4

5 0

3 years ago

The polynomial of degree 3, P(x), has a root of multiplicity 2 at x = 3 and a root of multiplicity 1 at x = -2. The y-intercept

Maru [420]

Answer:

$p(x) = - 0.7(x - 3)^{2} (x + 2)$

Step-by-step explanation:

We have that the polynomial, has a root of multiplicity 2 at x = 3 and a root of multiplicity 1 at x = -2.

This means the factored form of the polynomial will be.

$p(x) = a(x - 3)^{2} (x + 2)$

Also, it was given that, the y-intercept is y=-12.6.

This implies that:

$- 12.6= a(0 - 3)^{2} (0 + 2)$

$- 12.6= a(- 3)^{2} (2)$

$- 12.6= 18a$

Divide both sides by 18;

$a = \frac{ - 12.6}{18}$

$a= - 0.7$

Therefore the polynomial is

$p(x) = - 0.7(x - 3)^{2} (x + 2)$

7 0

4 years ago

The diameter of a circle is 14 m. Find its area in terms of \piπ.

Lena [83]

43.96 is what i got! im sorry if i got it wrong

6 0

3 years ago

Read 2 more answers

Which of the following values are in the range of the function graphed below? Check all that apply. HELP PLEASE !!!!!

poizon [28]

The only answer is choice D) 6

Recall that the range is the set of possible y output values of a function. In other words, its the list of y coordinates for every point on the function curve.

In this case, the horizontal line has EVERY point on it with a y coordinate of y=6. Two such points are (0,6) and (2,6). No other y value is possible. No matter what x value we plug in, the output is always y = 6

Side Note: the domain appears to be from x = -3 to x = 5

3 0

3 years ago