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2 years ago

A shirt purchased for $20. The store owner will sell it for a 40% mark up. What will the new price be?

Mathematics

2 answers:

ElenaW [278]2 years ago

7 0

Answer:

$28

Step-by-step explanation:

So we know the shirt is $20, and the owner is raising the price by 40%. That means we are adding $20 to 40% of the cost of the shirt

$20 + 40%

So we have to figure out how much 40% of $20 is. To do that, you can use fraction or decimal type

40% is the same thing as 40/100 or 0.4. So you will multiply either of them by $20 to find how much 40% of $20 is.

40/100 * 20 = 8

0.4 * 20 = 8

Now we know that 40% of $20 is $8. So now we will add 8$ to $20

20 + 8 = 28

The new price will be $28

Kazeer [188]2 years ago

3 0

40%=0.4

0.4(20)
8(markup)

Shirt price=$20+ $8

New price=$28

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BartSMP [9]

Answer:

Small candies $=9$

Extra large candies $=12$

Step-by-step explanation:

Let small candies $=x$

Extra large candies $=y$

the number of candies is at least $20$ .

$x+y\geq20$

Cost of $1$ small candy $=\$4$

Cost of $1$ extra large candy $=\$12$

but she has only $\$180$ to spend

$4x+12y\leq180$

Solve for

$x+y=20.......(1)\\4x+12y=180.....(2)\\eqn(2)-eqn(1)\times4\\8y=100\\y=\frac{100}{8} \\y=\frac{25}{8} \\from\ eqn(1)\\x+\frac{25}{2}=20\\ x=20-\frac{25}{2} \\x=\frac{15}{2}$

Since number of candies should be integer.

let $x=7,y=13$

total spend $4\times7+12\times13=184$ which is more than $\$180$ , so this combination is not possible.

$let\ x=8,y=12\\8\times4+12\times12=176$

She has $\$4$ more so she can buy $1$ more small candy.

Hence small candy $=9$

extra large candy $=12$

4 0

2 years ago

due to recent damand, target is rasing the price of a certain video game by 24%. If the game previously sold for $25, what was t

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Answer:

The number of students that bring their lunches is 12

Step-by-step explanation:

Let

x -----> the number of students that bring their lunches

y -----> the total number of students in a class

we know that

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$\frac{x}{y}=\frac{3}{8}$

$x=\frac{3}{8}y$ -----> equation A

$y=32$ -----> equation B

substitute the value of y in equation A and solve for x

$x=\frac{3}{8}(32)$

$x=12$

therefore

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Answer:

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