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3 years ago

A decorative gift box is in the shape of a triangular prism as shown. what is the surface area of the box

Mathematics

1 answer:

madreJ [45]3 years ago

7 0

Answer:

the anser

Step-by-step explanation:

this is faze jarvis hahah

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Which transformations are needed to change the parent cosine function to the cosine function below? On a coordinate plane, a cur

Nastasia [14]

Answer:

vertical compression of One-half, horizontal stretch to a period of 4 pi, vertical shift of 1 unit up, phase shift of Pi units left

Step-by-step explanation:

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3 years ago

What is the side length, in inches, of the pets

tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is $4x-5$ inches

Step-by-step explanation:

Given

Area of the square of design = $16x^{2} -40x+25$

First we find the roots of equation $16x^{2} -40x+25=0$

The roots of the quadratic equation $ax^{2} +bx^{2} +c=0$ are given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where $a=16, b=-40, c=25$

$x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}$

$x=\frac{40\pm\sqrt{1600-1600}}{32}$

$x=\frac{40\pm\sqrt{0}}{32}$

$x=\frac{40}{32}$

$x=\frac{5}{4}$

$4x=5\\4x-5=0$

That is, the factors of the polynomial $16x^{2} -40x+25$ are $4x-5$ and $4x-5$ .

So, Area of the square design = $16x^{2} -40x+25$ = $(4x-5)^{2}$

Area of a square = Length^2

Thus, the length of the sign is $4x-5$ inches

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3 years ago

Help plz Ik its a lot but I will give you 40

timama [110]

Answer:

1. 343

2. 64

3. 81

4. 12.25

Step-by-step explanation:

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The factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50 and 100. To find the prime factorization, first take any two of the factors that multiply to make 100. For instance, 25 x 4 = 100. Neither 25 nor four is a prime number, so each must be broken down further
There you go =)

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Genrish500 [490]

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All parallelograms are quadrilaterals

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