I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is
x+1=0; x+1=0
In this case, the factors are the same so the root of the equation is
x=1.
The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.
Answer:
(x−2)^3=x^3−6x^2+12x-8
Step-by-step explanation:
if you are talking about the binomial (x−2)^3 you must expand then simplify. (x-2)3 you would just remove the parenthesizes and multiply -2 with 3 to get x-6 but I think you meant (x-2)^3
Answer:
The first picture is B and the second one is (0,-3)
It is no answer, because when you get 12x + 48 = 48 + 12x, they cancel each other out.
Pretty sure it’s 4 idk tho this is a tough one. Hahahaha
