A^2 + 3b + c - 2d
(3)^2 + 3(8) + (2) - 2(5)
9 + 24 + 2 - 10 = 25
A_n= a₁+(n-1)d
a₁ first term
n terms
d distance between each value
a_n= 12+(405-1)(5)=2032
90/2=45
45/3=15
15/3=5
90=2*3*3*5=2¹*3²*5¹
Answer:
17
Step-by-step explanation:
Pythagorean theory baby! Okay so the Pythagorean theory is a² + b² = c² so lets draw a triangle and label our sides. So we know 8² + 15² = c² so I'm going to find the square root of all of our numbers. We get 64 + 225 = c² so then add 64 + 225 = 289 then I take the square root of 289 which equals 17 . This answer also makes sense because out hypotenuse should always be bigger then the legs.
I'm pretty sure thats right, Hope this helps.