All categories

3 years ago

How many groups of 12 are in 600

Mathematics

1 answer:

harina [27]3 years ago

5 0

600 ÷ 12 = 50

Answer: There are 50 groups of 12 in 600

You might be interested in

Which function has the same graph as x + y = 112 OA x) = -y + 11 OB. f(x) = -x + 11 Oc. x) = x- 11 O D. x) = y-11

Lera25 [3.4K]

Answer:

B. f(x) = -x + 11

Step-by-step explanation:

First if you rearrange the equation you get f(x) = -x + 11, like this:

x + y = 11

Minus x from both sides

y = -x + 11

F(x) and y are interchangeable so we just put f(x) in

f(x) = -x + 11

Each of the graphs are attached and we see that they are the same!

Hope this helps!!

- Kay

4 0

2 years ago

Please answerrrr Graph g(x), where f(x) = 4x − 2 and g(x) = f(x + 1). a line labeled g of x that passes through points 0, negati

Mrrafil [7]

Answer:

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

Step-by-step explanation:

we have

$f(x)=4x-2$

$g(x)=f(x+1)$

To determine g(x), substitute the variable x by (x+1) in the function f(x)

$f(x+1)=4(x+1)-2$

$f(x+1)=4x+4-2$

$f(x+1)=4x+2$

$g(x)=f(x+1)$

$g(x)=4x+2$

therefore

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

4 0

3 years ago

Read 2 more answers

Basic compounds produce OH- ions when dissolved in water. true or false

Ket [755]

Answer:

Step-by-step explanation:

4 0

3 years ago

TJ-Maxx offered a 36% discount off the original price of a head board. The amount of the discount is $9. What is the regular pri

jok3333 [9.3K]

The amount if the original cost of the head board is $12.24

5 0

2 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

7 0

3 years ago

Read 2 more answers