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3 years ago

How many groups of 12 are in 600

Mathematics

1 answer:

harina [27]3 years ago

5 0

600 ÷ 12 = 50

Answer: There are 50 groups of 12 in 600

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Suppose the linear cost function C(x) = 6x gives the cost for buying x items. If the items are sold in packages of 10, and no on

Damm [24]

X=the number of packages of 10. So: 1 ≾ x ≾ 5.

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3 years ago

Read 2 more answers

An SRS of 27 students at UH gave an average height of 5.6 feet and a standard deviation of .1 feet.Construct a 90% confidence in

Juliette [100K]

Answer:

Option a) [5.567, 5.633]

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ = 5.6 feet

Sample size, n = 27

Alpha, α = 0.10

Sample standard deviation, s = 0 .1 feet

90% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 26 and}~\alpha_{0.10} = \pm 1.7056$

$5.6 \pm 1.7056(\displaystyle\frac{0.1}{\sqrt{27}} ) = 5.6 \pm 0.0328 = (5.5672 ,5.6328) \approx (5.567,5.633)$

Option a) [5.567, 5.633]

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3 years ago

What are the new coordinates of (6,-2) with the dilation scale factor of 1/2.

In-s [12.5K]

Answer:

(3, - 1 )

Step-by-step explanation:

Assuming the dilatation is centred at the origin then multiply each coordinate by $\frac{1}{2}$

(6, - 2 ) → (6 × $\frac{1}{2}$ , - 2 × $\frac{1}{2}$ ) → (3, - 1 )

4 0

2 years ago

Compare the perimeters of the two regular figures. Which statement is true?

adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

Since, hexagon consists of 6 sides and 6 angles, thus the measure of one angle of the hexagon will be= $\frac{(n-2){\timeS}180^{\circ}}{6}$

= $\frac{(6-2){\timeS}180^{\circ}}{6}$

= $\frac{(4){\timeS}180^{\circ}}{6}$

= $120^{\circ}$

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

$\frac{MP}{MQ}=cos60^{\circ}$

$MP=\frac{1}{2}$

Thus, the perimeter of the hexagon is:

$P=12{\times}MP$

$P=12{\times}\frac{1}{2}$

$P=6 units$

Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be= $\frac{(n-2){\timeS}180^{\circ}}{8}$

= $\frac{(8-2){\timeS}180^{\circ}}{8}$

= $\frac{(6){\timeS}180^{\circ}}{8}$

= $135^{\circ}$

Now, since AP is the angle bisector of the one of the angle of the octagon, therefore ${\angle}PAC=cos\frac{135}{2}$ .

From ΔAPC, we have

$AC=cos\frac{135}{2}$

Now, Perimeter of octagon is:

$P=16{\times}cos\frac{135}{2}$

$P=16{\times}0.382$

$P=6.122 units$

Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.

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3 years ago

The table shows the price for different numbers of icecream treats:

Natasha2012 [34]

The answer is a, yes

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2 years ago