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alisha [4.7K]
3 years ago
11

How many groups of 12 are in 600

Mathematics
1 answer:
harina [27]3 years ago
5 0

600 ÷ 12 = 50


Answer: There are<u> 50</u> groups of 12 in 600

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I need to increase the numbers of customers I talk to daily by 20%. I talk to an average of 8 customers per hour during an 8 hou
irina [24]

Answer:77

Step-by-step explanation:Talk to 8 customers per hour, work 8 hours, so:Talk to 8*8 = 64 customers.

Has to increase by 20%, so 64 is multiplied by 1 + 0.2 = 1.2. Then64*1.2 = 76.8Rounding up, 77 is the answer.

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Light travels at 186,000 miles per second. How many FEET does it travel in a microsecond? (A microsecond is a millionth of a sec
Maslowich
1 mile is 5,280 ft, and 1 second has 1,000,000 microseconds.
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Answer:

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3 years ago
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Find the rational roots f(x) =3x3+ 2x2 + 3x + 6
Ann [662]

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

<h3>How to determine the rational root of the function f(x)?</h3>

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 3

b = 6

The factors of 3 and 6 are

a = 1 and 3

b = 1, 2, 3 and 6

So, we have:

Rational roots = ±(1, 2, 3, 6)/(1, 3)

Split the expression

Rational roots = ±(1, 2, 3, 6)/1 and ±(1, 2, 3, 6)/3

Evaluate the quotient

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3, 1, 2)

Remove the repetition

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3)

Hence, the rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

Read more about rational roots at

brainly.com/question/17754398

#SPJ1

4 0
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How to find The point midway
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Step-by-step explanation:

The Midpoint Formula works exactly the same way. If you need to find the point that is exactly halfway between two given points, just average the x-values and the y-values.

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