3. Any number you choose between 7 and 3
4. Any number you choose below 8
Answer:
The sigma capability of the process is 5.2857
Step-by-step explanation:
The sigma capability of a process is defined by the number of times that the distance between the lower specification limit and the upper specification limit contains the value of the standard deviation. In this case:
(USL - LSL) / sd = (247 - 265.5) / 3.5 = 5.2857
Then, the sigma capability of the process is 5.2857
Answer:
The answer would be the bottom left, sorry I don't know what letter that is.
Step-by-step explanation:
<h2>
Explanation:</h2><h2>
</h2>
Here we know that an internet service provider is implementing a new program based on the number of connected devices in each household. Currently, customers are charged a flat rate of $175 per month. Assuming just a month, we can write a constant equation given by the form:
![y=175 \\ \\ \\ Where: \\ \\ y:\text{Cost in dollars}](https://tex.z-dn.net/?f=y%3D175%20%5C%5C%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20y%3A%5Ctext%7BCost%20in%20dollars%7D)
The new plan would charge a flat rate of $94 plus an additional $4.50 per device connected to the network. So the linear equation is:
![y=94+4.5x \\ \\ \\ Where: \\ \\ x:\text{Number of months} \\ \\ y:\text{Number of devices}](https://tex.z-dn.net/?f=y%3D94%2B4.5x%20%5C%5C%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20x%3A%5Ctext%7BNumber%20of%20months%7D%20%5C%5C%20%5C%5C%20y%3A%5Ctext%7BNumber%20of%20devices%7D)
So we need to find the number of devices, x, for which the cost of the new plan is less than the cost of the current plan. By using inequalities:
![94+4.5x](https://tex.z-dn.net/?f=94%2B4.5x%3C175%20%5C%5C%20%5C%5C%204.5x%3C81%20%5C%5C%20%5C%5C%20x%3C%5Cfrac%7B81%7D%7B4.5%7D%20%5C%5C%20%5C%5C%20x%3C18)
<em>So you should connect less than 18 devices in a month in order for the cost of the new plan to be less than the cost of the current plan.</em>
Answer:
(x+2)(x+8)=0
Step-by-step explanation:
the first term x² can only be factored by (x) times(x), and the last term 16 has factors of 16&1, 4&4 or 8&2. only 8 &2 have a sum of 10x (the middle term) so
(x+2)(x+8)=0